Answer:
Both are correct.
Step-by-step explanation:
The key understanding here is that you can factor a monomial in many different ways!
To check if any of the factorizations is correct, we can multiply the factors and see if their product is really 12x^712x
7
12, x, start superscript, 7, end superscript.
Hint #22 / 4
\begin{aligned} (\blueD{4}\maroonD{x^3})(\blueD{3}\maroonD{x^4})&=(\blueD{4})(\blueD{3})(\maroonD{x^3})(\maroonD{x^4}) \\\\ &=\blueD{12}\maroonD{x^7} \end{aligned}
(4x
3
)(3x
4
)
=(4)(3)(x
3
)(x
4
)
=12x
7
So Ibuki is correct!
Hint #33 / 4
\begin{aligned} (\blueD{2}\maroonD{x^6})(\blueD{6}\maroonD{x})&=(\blueD{2})(\blueD{6})(\maroonD{x^6})(\maroonD{x}) \\\\ &=\blueD{12}\maroonD{x^7} \end{aligned}
(2x
6
)(6x)
=(2)(6)(x
6
)(x)
=12x
7
So Melodie is also correct!
Both Ibuki and Melodie are correct.
24 times 3= 72+4=76+14=90
^
Answer:
dư 0... 7^300 chia 7 đc 7^299 mà
You would start by saying his budget is $80 so you start with 80= he pays an initial fee of $59.50 every month plus $5 per gigabyte so you would set it up like
80=59.50+5x
X being how many gigabytes he uses then you solve 80-59.50 is 20.5 divided by 5 gives you 4.1 but you round down cause you don’t want to pass the limit so therefor the most gigabytes he can use is 4
