The equations to calculate the legs are 0.5(x)(x + 2) = 24, x^2 + 2x - 48 = 0 and x^2 + (x + 2)^2 = 100
<h3>How to determine the legs of the triangle?</h3>
The complete question is in the attached image
The given parameters are:
Area = 24
Legs = x and x + 2
The area of the triangle is calculated as:
Area = 0.5 * Base * Height
This gives
0.5 * x * (x + 2) = 24
So, we have:
0.5(x)(x + 2) = 24
Divide through by 0.5
(x)(x + 2) = 48
Expand
x^2 + 2x = 48
Subtract 48 from both side
x^2 + 2x - 48 = 0
Hence, the equations to calculate the legs are 0.5(x)(x + 2) = 24, x^2 + 2x - 48 = 0 and x^2 + (x + 2)^2 = 100
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Yes! In △RST, VT=60 in. What is the length of TX¯¯¯¯¯? It is 40 in.
Answer:
a = 55/6
Step-by-step explanation:
<u>Solving in steps:</u>
- 3/5a = 5 1/2
- 3/5a = 11/2
- a = 11/2 : 3/5
- a = 11/2*5/3
- a = 55/6 or 9 1/6
12+4+9+13+7+11+5+2+_+_ /10= 8
x10 both sides
12+4+9+13+7+11+5+2+_+_=80
63+_+_=80
-63 both sides
_+_= 17
any two numbers that add up to 17 can go in the planks
7,10
Answer:
<em> (a). ∠UXV, ∠XVY ; (b). UV = 8 m .</em>
Step-by-step explanation: