Answer:
0, for q ≠ 0 and q ≠ 1
Step-by-step explanation:
Assuming q ≠ 0, you want to find the value of x such that ...
q^x = 1
This is solved using logarithms.
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x·log(q) = log(1) = 0
The zero product rule tells us this will have two solutions:
x = 0
log(q) = 0 ⇒ q = 1
If q is not 0 or 1, then its value is 1 when raised to the 0 power. If q is 1, then its value will be 1 when raised to <em>any</em> power.
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<em>Additional comment</em>
The applicable rule of logarithms is ...
log(a^b) = b·log(a)
Answer:
4/5 x 7/12 = 28/60 as simplified as 7/15 in fraction form. 4/5 x 7/12 = 0.4667 in decimal form.
Answer:
w = 21
Step-by-step explanation:
i've done this kind of thing before a million times
Answer:
Range is number of copies produced and set of values is; 1 ≤ N ≤ 200
Domain; Cost of publishing book in dollars; set of values are; $710 ≤ N ≤ $2700
Step-by-step explanation:
Range is a set of all the possible output values in a function while domain is the set of all possible input values.
Now, the function is given as;
C = 10N + 700
Where;
C is the cost of publishing the book in dollars
N is the number of copies of books produced
Thus, the domain will be a set of N values while Range will be a set of C values.
We are told that the first printing can produce up to 200 copies of the book.
That means a maximum of 200 books and a minimum of 1.
Thus;
Range is; 1 ≤ N ≤ 200
Maximum possible cost of the 200 books is;
C = 10(200) + 700
C = $2700
Minimum cost which will be for 1 book will be;
C = 10(1) + 700
C = $710
Thus,domain is;
$710 ≤ N ≤ $2700
Because it is the same by the 0 and the 0 represents as a place holder for the 32
