<h3>The distance between the pair of points is 2.8 units</h3>
<em><u>Solution:</u></em>
Given that,
Points are W(2, 5), U(4, 3)
<em><u>Distance between two points is given as:</u></em>
![d = \sqrt{(y_2-y_1)^2 + (x_2-x_1)^2}](https://tex.z-dn.net/?f=d%20%3D%20%5Csqrt%7B%28y_2-y_1%29%5E2%20%2B%20%28x_2-x_1%29%5E2%7D)
From given,
![(x_1, y_1) = (2, 5)\\\\(x_2, y_2) = (4, 3)](https://tex.z-dn.net/?f=%28x_1%2C%20y_1%29%20%3D%20%282%2C%205%29%5C%5C%5C%5C%28x_2%2C%20y_2%29%20%3D%20%284%2C%203%29)
<em><u>Substituting the values we get,</u></em>
![d = \sqrt{(3-5)^2+(4-2)^2}\\\\d = \sqrt{(-2)^2 + (2)^2}\\\\ d = \sqrt{4+4}\\\\d = \sqrt{8}\\\\d = 2.8284](https://tex.z-dn.net/?f=d%20%3D%20%5Csqrt%7B%283-5%29%5E2%2B%284-2%29%5E2%7D%5C%5C%5C%5Cd%20%3D%20%5Csqrt%7B%28-2%29%5E2%20%2B%20%282%29%5E2%7D%5C%5C%5C%5C%20d%20%3D%20%5Csqrt%7B4%2B4%7D%5C%5C%5C%5Cd%20%3D%20%5Csqrt%7B8%7D%5C%5C%5C%5Cd%20%3D%202.8284)
![d \approx 2.8](https://tex.z-dn.net/?f=d%20%5Capprox%202.8)
Thus the distance between the pair of points is 2.8 units
Answer:
C
Step-by-step explanation:
If this helped, please mark me as brainliest.
Answer:
the first one is y=x-1/2 and the second one is y=-3x+1
Step-by-step explanation:
As a rule option A is the answer to a degree
<span>109.464285714 should be the answer double check first :)</span>