Y<=2x+3
y=2x+3
x=0→y=2(0)+3=0+3→y=3→Point=(x,y)=(0,3)
y=0→0=2x+3→2x+3=0→2x+3-3=0-3→2x=-3→2x/2=-3/2→x=-1.5→
Point=(x,y)=(-1.5,0)
y<=2x+3 is the region below the right line passes trough the points (0,3) and (-1.5,0)
3x+y<=-2
3x+y-3x<=-2-3x
y<=-3x-2
y=-3x-2
x=0→y=-3(0)-2=0-2→y=-2→Point=(x,y)=(0,-2)
y=0→0=-3x-2→-3x-2=0→-3x-2+2=0+2→-3x=2→-3x/(-3)=2/(-3)→x=-2/3→
x=-0.67→Point=(x,y)=(-0.67,0)
y<=-3x-2 is the region below the right line passes trough the points (0,-2) and (-0.67,0)
Answer: First graph
42/100 of X = 63 is the equation. Therefore solving this gives you 150 dancers in total. Hope this helps.
Answer:this is an example
Step-by-step explanation:2A (5, 2)Graph A(5, 2), then graph B, the image of A under a 90° counterclockwise
Answer:
Identity property of multiplication
Step-by-step explanation:
