The answer is 1/12.
The perimeter of a square garden with side s is:
P = 4s
s = 1/4P
Since it is painted 1/3 of 1/4 of the fence, the<span> fraction of the painted fence is:
1/3 * 1/4 = 1/12</span>
I'm not sure if this is correct but you would put it into an equation while you solve for X. so 0.75x=150 or equivalently would be like (3/4)x=150 Then after that you would divide both sides by 0.75 or 3/4
Answer:
Net Change in Geno's Field Position = 22 yards
Step-by-step explanation:
Assuming Geno initial position before change is 0
Geno Gained 4 yards three times = 4*3 = 12yards
Geno lose 1 yard twice = 1*(-2) = -2yards
Geno Gained 6 yards twice = 6*2 = 12yards
Net Change in Geno's Field Position = 12 + (-2) + 12 yards
= 22 yards
The answer is not defined.
Explanation:
The given matrix is ![$\left[\begin{array}{cc}{2} & {4} \\ {1} & {-6}\end{array}\right]+\left[\begin{array}{c}{1} \\ {0}\end{array}\right]$](https://tex.z-dn.net/?f=%24%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D%7B2%7D%20%26%20%7B4%7D%20%5C%5C%20%7B1%7D%20%26%20%7B-6%7D%5Cend%7Barray%7D%5Cright%5D%2B%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D%7B1%7D%20%5C%5C%20%7B0%7D%5Cend%7Barray%7D%5Cright%5D%24)
The matrix
has dimensions 
This means that the matrix has 2 rows and 2 columns.
Also, the matrix
has dimensions 
This means that the matrix has 2 rows and 1 column.
Since, the matrices can be added only if they have the same dimensions.
In other words, to add the matrices, the two matrices must have the same number of rows and same number of columns.
Since, the dimensions of the two matrices are not equal, the addition of these two matrices is not possible.
Hence, the addition of these two matrices is not defined.
4200
Step-by-step explanation:
10 × 150 = 1500
18 × 150 = 2700
So
1500 + 2700 = 4200