The answer to this question is false because it cannot still be both negative after you reflect over two positives.
Answer:
This is true.
Step-by-step explanation:
Step 1: see that √27 is the same as √3*3*3 and thus 3√3
Step 2: remove parenthesis so that 2(1-3√3) becomes 2 - 6√3
Step 3: observe that the equation now becomes 6√3 + 2 - 6√3 = 2
if you simplify any further, you are left with 0=0, which is true.
Comment if there is any step that requires more details...
Bearing means there is a rightangled triangle so
we've got an angle of 90°
an angle of 50°
sum triangle is 180
180- (90 + 50 )
= 180 - 140
= 40°
The anser is 11 you can see
Answer:
D. (1, -2)
General Formulas and Concepts:
<u>Pre-Algebra</u>
- Order of Operations: BPEMDAS
- Equality Properties
<u>Algebra I</u>
- Solving systems of equations using substitution/elimination
Step-by-step explanation:
<u>Step 1: Define systems</u>
5x - 2y = 9
3x + 4y = -5
<u>Step 2: Rewrite systems</u>
10x - 4y = 18
3x + 4y = -5
<u>Step 3: Solve for </u><em><u>x</u></em>
- Add to equations together: 13x = 13
- Divide 13 on both sides: x = 1
<u>Step 4: Solve for </u><em><u>y</u></em>
- Define: 3x + 4y = -5
- Substitute in <em>x</em>: 3(1) + 4y = -5
- Multiply: 3 + 4y = -5
- Isolate <em>y </em>term: 4y = -8
- Isolate <em>y</em>: y = -2
And we have our final answer!