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3 years ago

Which is equivalent to “4 pencils for every 2 students”?

Mathematics

1 answer:

TiliK225 [7]3 years ago

4 0

Answer:

8 pencils for every 4 students or 2 pencils for every students

Step-by-step explanation:

Whatever you want to multiply or divide one from, you gotta do it to the other number so it can stay equivalent

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Y = -x + 5<br> Write in standard form. PLEASE SHOW WORK! WILL GIVE BRAINLY!

strojnjashka [21]

Answer:

x+y=5

Step-by-step explanation:

y=-x+5

add x to both sides

x+y=5

8 0

3 years ago

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Gemma's soup recipe is shown in the table above.What is the radio of chicken stock to mixed vegetables? Express the ratio as a f

mars1129 [50]

Ratio of chicken stock to mixed vegetables is 3.5 to 8

3 0

3 years ago

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c(1)=−20 c(n)=c(n−1)+10 Find the 2nd term in the sequence.

Bad White [126]

Answer:

-10 is the second term.

Step-by-step explanation:

After the first term each term is obtained from the previous one by adding 10.

c(1) = -20

so c(2) = -20 + 10

= -10.

3 0

3 years ago

The market and Stock J have the following probability distributions:

denis-greek [22]

Answer:

1) $E(M) = 14*0.3 + 10*0.4 + 19*0.3 = 13.9 \%$

2) $E(J)= 22*0.3 + 4*0.4 + 12*0.3 = 11.8 \%$

3) $E(M^2) = 14^2*0.3 + 10^2*0.4 + 19^2*0.3 = 207.1$

And the variance would be given by:

$Var (M)= E(M^2) -[E(M)]^2 = 207.1 -(13.9^2)= 13.89$

And the deviation would be:

$Sd(M) = \sqrt{13.89}= 3.73$

4) $E(J^2) = 22^2*0.3 + 4^2*0.4 + 12^2*0.3 =194.8$

And the variance would be given by:

$Var (J)= E(J^2) -[E(J)]^2 = 194.8 -(11.8^2)= 55.56$

And the deviation would be:

$Sd(M) = \sqrt{55.56}= 7.45$

Step-by-step explanation:

For this case we have the following distributions given:

Probability M J

0.3 14% 22%

0.4 10% 4%

0.3 19% 12%

Part 1

The expected value is given by this formula:

$E(X)=\sum_{i=1}^n X_i P(X_i)$

And replacing we got:

$E(M) = 14*0.3 + 10*0.4 + 19*0.3 = 13.9 \%$

Part 2

$E(J)= 22*0.3 + 4*0.4 + 12*0.3 = 11.8 \%$

Part 3

We can calculate the second moment first with the following formula:

$E(M^2) = 14^2*0.3 + 10^2*0.4 + 19^2*0.3 = 207.1$

And the variance would be given by:

$Var (M)= E(M^2) -[E(M)]^2 = 207.1 -(13.9^2)= 13.89$

And the deviation would be:

$Sd(M) = \sqrt{13.89}= 3.73$

Part 4

We can calculate the second moment first with the following formula:

$E(J^2) = 22^2*0.3 + 4^2*0.4 + 12^2*0.3 =194.8$

And the variance would be given by:

$Var (J)= E(J^2) -[E(J)]^2 = 194.8 -(11.8^2)= 55.56$

And the deviation would be:

$Sd(M) = \sqrt{55.56}= 7.45$

8 0

3 years ago

There are 30 students in Mrs. Woodward’s class, and 1/5 of the class has their own cell phone. Of this group of students, 1/2 of

olga_2 [115]

Answer:

3 students

Step-by-step explanation:

There are 30 students in Mrs. Woodward’s class.

$\dfrac{1}{5}$ of the class has their own cell phone, so

$\dfrac{1}{5}\cdot 30=\dfrac{1}{5}\cdot \dfrac{30}{1}=6$

students have their own cell phones.

$\dfrac{1}{2}$ of those 6 students are allowed to use social media. So,

$\dfrac{1}{2}\cdot 6=\dfrac{1}{2}\cdot \dfrac{6}{1}=3$

students are allowed to use social media.

3 0

3 years ago