Group and factor
undistribute then undistribute again
remember
ab+ac=a(b+c)
this is important
6d^4+4d^3-6d^2-4d
undistribute 2d
2d(3d^3+2d^2-3d-2)
group insides
2d[(3d^3+2d^2)+(-3d-2)]
undistribute
2d[(d^2)(3d+2)+(-1)(3d+2)]
undistribute the (3d+2) part
(2d)(d^2-1)(3d+2)
factor that difference of 2 perfect squares
(2d)(d-1)(d+1)(3d+2)
77.
group
(45z^3+20z^2)+(9z+4)
factor
(5z^2)(9z+4)+(1)(9z+4)
undistribuet (9z+4)
(5z^2+1)(9z+4)
First and last terms of the given equation are perfect squares. They can be written as
(4p^2)^2+ 2.(4p^2).5+(5)^2
It's like identity 1: (a+b)^2=a^2+2ab+b^2
So a=4p^2 and b=5
Therefore it is equal to (4p^2+5)^2
<u>Given:</u>
The angle of elevation from the point on the ground to the top of the tree is 34° and the point is 25 feet from the base of the tree.
We need to determine the height of the tree.
<u>Height of the tree:</u>
Let the height of the tree be h.
The height of the tree can be determined using the trigonometric ratio.
Thus, we have;

Substituting the values, we get;

Multiplying both sides by 25, we have;



Rounding off to the nearest tenth of a foot, we get;

Thus, the height of the tree is 16.9 feet.
Hence, Option B is the correct answer.
92 = 11 + 12 + 13 + 2(a) + 4(3a)
92 = 36 + 2a + 12a
92 = 36 + 14a
-36 -36
56 = 14a
56/14 = 14a/14
a = 4
Answer:
i believe it is y=50x+40
Step-by-step explanation: