1. 231 ft/s = (231 ft/s)*(1 m/(3.3 ft)) ≈ 70 m/s
2. In 10 seconds, the parachutist will fall
.. (10 s)*(70 m/s) = 700 m
Answer:
10% Change
10% increase
Step-by-step explanation:
Hope this helps!
Answer:
a.)Q' = -kQ + r
b.)Q =
c.) Limiting long run value of Q =
Step-by-step explanation:
a.)
The rate of change is directly proportional to the quantity, Q
⇒ ∝ Q
⇒ = -kQ ( because it is decreasing )
Also given, quantity is increasing with a constant rate r
⇒ = -kQ + r
⇒Q' = -kQ + r
b.)
As we have
= -kQ + r
⇒ = dt
⇒∫ = ∫dt
⇒-
⇒log(-kQ + r) = -kt -kC
Taking exponential both side, we get
⇒-kQ + r =
⇒-kQ = -r +
⇒Q = -
⇒Q = -
⇒Q = - .......(1)
Now,
At t = 0, Q = 0
0 = - B
⇒
⇒B = r
∴ equation (1) becomes
Q = -
⇒Q =
c.)
for limiting long run value of Q
=
=
⇒Limiting long run value of Q =
Answer:
(x+5)(x-4)(x-3)
Step-by-step explanation:
Divide (e+5) into e³-2e²-23e+60 using polynomial long division (picture attached below). Since it divides in evenly, we can see it is a factor.
So we can say e³-2e²-23e+60 = (e+5)(e²-7e+12)
To complete the factorisation, factorise e²-7e+12.
Note that (x+a)(x+b)=x²+(a+b)x+ab. So find the multiples or 12 which can be added or subtracted to get -7: -4 and -3.
e²-7e+12=(x-4)(x-3)
So e³-2e²-23e+60 = (x+5)(x-4)(x-3)