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lisabon 2012 [21]
3 years ago
15

Drawing a card- four cards are drawn from a desk without replacement.Find these probabilities.

Mathematics
1 answer:
svetlana [45]3 years ago
5 0

The deck consists of 4 jacks, 26 black cards, and 13 hearts.

There is only 1 way of drawing all 4 jacks: \dbinom44=\dfrac{4!}{4!(4-4)!}=1.

There are \dbinom{26}4=14,950 ways of drawing 4 black cards.

There are \dbinom{13}4=715 ways of drawing 4 hearts.

There are \dbinom{52}4=270,725 ways of drawing any 4 cards.

The probabilities are then

a.

\dfrac{\binom44}{\binom{52}4}=\dfrac1{207,725}\approx0.00000369

b.

\dfrac{\binom{26}4}{\binom{52}4}=\dfrac{46}{833}\approx0.0552

c.

\dfrac{\binom{13}4}{\binom{52}4}=\dfrac{11}{4165}\approx0.00264

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If a drug has a concentration of 8.22 mg per 3.039 mL, how many mL are needed to give 7.469 gram of the drug? Round to 1 decimal
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Answer:

2.8 litres

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3 years ago
The random variable x has the following probability distribution: x f(x) 0 .25 1 .20 2 .15 3 .30 4 .10 a. Is this probability di
Reptile [31]

Answer and Explanation:

Given : The random variable x has the following probability distribution.

To find :

a. Is this probability distribution valid? Explain and list the requirements for a valid probability distribution.

b. Calculate the expected value of x.

c. Calculate the variance of x.

d. Calculate the standard deviation of x.

Solution :

First we create the table as per requirements,

x      P(x)         xP(x)           x²            x²P(x)

0    0.25           0               0                0

1     0.20        0.20             1              0.20

2    0.15          0.3               4             0.6

3    0.30         0.9               9             2.7

4    0.10          0.4               16             1.6

   ∑P(x)=1     ∑xP(x)=1.8               ∑x²P(x)=5.1

a) To determine that table shows a probability distribution we add up all five probabilities if the sum is 1 then it is a valid distribution.

\sum P(X)=0.25+0.20+0.15+0.30+0.10

\sum P(X)=1

Yes it is a probability distribution.

b) The expected value of x is defined as

E(x)=\sum xP(x)=1.8

c) The variance of x is defined as

V=\sum x^2P(x)-(\sum xP(x))^2\\V=5.1-(1.8)^2\\V=5.1-3.24\\V=1.86

d) The standard deviation of x is  defined as

\sigma=\sqrt{V}

\sigma=\sqrt{1.86}

\sigma=1.136

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3 years ago
The simplified form of an expression is 1 . Which expression was simplified?
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