What are the coordinates of the midpoint of ab?
2 answers:
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Answer:
Step-by-step explanation:
Hi!
Lets call:
T = temprature of the object
T₀ = temperature of surroundings
t = time
The rate of change of T is its derivative with respecto to time. If T > T₀, the object looses heat, so T decreases. Then, being k > 0:
In this case T₀ = 70ºF and k = 0.05/min. Then the differential equation is:
It is parallel, which means that the new line should have the same slope of the given line 
and the slope is the coefficient of x
so the slope = -5/4
in order to solve this problem we have to know the equation of the slop
where (x1,y1) is the point by which the new line passes through
-5(x-1)=4(y+4)
-5x +5=4y+16 (by subtracting 16 from both sides)
-5x -11= 4y (divide both sides by 4)
y=
and the slope is the coefficient of x
so the slope = -5/4
in order to solve this problem we have to know the equation of the slop
where (x1,y1) is the point by which the new line passes through
-5(x-1)=4(y+4)
-5x +5=4y+16 (by subtracting 16 from both sides)
-5x -11= 4y (divide both sides by 4)
y=