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Citrus2011 [14]
3 years ago
11

What is the area of the trapezoid with height 10 units? Enter your answer in the box. units2 A rectangle with a length of 5 and

a height of 10 has two triangles on each side of it with long leg lengths of 12.
Mathematics
2 answers:
Novay_Z [31]3 years ago
4 0
170 Units2
That's the answer. 
Brainliest, please! :)

<3 <3 <3 <3
LenaWriter [7]3 years ago
3 0
If by "long leg lengths" you mean the hypotenuse then the area is 116 sq. units.  If you mean the bases of the triangles then the area is 170 sq. units.

If the length of 12 is the hypotenuse, we first must find the base of the triangles using the Pythagorean theorem:

10² + b² = 12²
100 + b² = 144
b² = 44
b = √44 = 6.6

This means we have two triangles and a rectangle.  The area of the rectangle is 5(10) = 50 sq. units.  The area of each triangle is 1/2(6.6)(10) = 33.  Adding all 3 together we have:

50+33+33 = 116 sq. units.

If the 12 is the base, then we have the rectangle with the area of 5(10) = 50 and two triangles each with an area of 1/2(12)(10) = 60:

50+60+60 = 170 sq. units.
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$3,500 at 10% and $6,500 at 7%.

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How much chromium-51 will be left after 7 months?
Makovka662 [10]

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It seems there's more information in you question that you haven't posted.

7 months = 7 * (365/12) = 213 days

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To solve for the ending amount we'll use the formula:

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Basicaly if you started with 1 gram of chromium 51, after 7 months you would have 0.0048426082 grams.

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Step-by-step explanation:

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Step-by-step explanation:

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Find the linearization L(x) of the function at a. <br> f(x) = x3/4, a = 81
Zolol [24]

Please note that your x^3/4 is ambiguous.  Did you mean (x^3)  divided by 4
or did you mean x to the power (3/4)?  I will assume you meant the first, not the second.  Please use the "^" symbol to denote exponentiation.

If we have a function f(x) and its derivative f'(x), and a particular x value (c) at which to begin, then the linearization of the function f(x) is

f(x) approx. equal to  [f '(c)]x + f(c)].

Here a = c = 81.

Thus, the linearization of the given function at a = c = 81 is

f(x) (approx. equal to)  3(81^2)/4 + [81^3]/4

Note that f '(c) is the slope of the line and is equal to (3/4)(81^2), and f(c) is the function value at x=c, or (81^3)/4.

What is the linearization of f(x) = (x^3)/4, if c = a = 81?

It will be f(x) (approx. equal to) 
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