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3 years ago

6

21. If there are 6 air conditioners and each require 8 pounds of refrigerant, how many pounds of

1 answer:

djyliett [7]3 years ago

5 0

It’s 48 because 8x6=48

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John states that all trapezoids have at least one line of symmetry.

IrinaK [193]

A
bc i got it right

7 0

2 years ago

What is the measure of m?<br><br> n<br><br> 28<br><br> m<br><br> 7<br><br> V[?]<br><br> m =

Semenov [28]

Answer:

y geometric mean property,n² = 28 × 7 = 196n = 14.By pythagorean

Step-by-step explanation:

8 0

2 years ago

I need help pleaseee

kumpel [21]

Answer: $7448

Step-by-step explanation:

Year 1: 1.218x

Year 2: 1.218(1.218x)

Year 3: 1.218(1.218(1.218x))

Year 4: 1.218(1.218(1.218(1.218x)))

Year 5: 1.218(1.218(1.218(1.218(1.218x))))

Year 6: 1.218(1.218(1.218(1.218(1.218(1.218x)))))

Year 7: 1.218(1.218(1.218(1.218(1.218(1.218(1.218x))))))

Year 8: 1.218(1.218(1.218(1.218(1.218(1.218(1.218(1.218x)))))))

Year 9: 1.218(1.218(1.218(1.218(1.218(1.218(1.218(1.218(1.218x))))))))

Year 10: 1.218(1.218(1.218(1.218(1.218(1.218(1.218(1.218(1.218(1.218x)))))))))

Year 11: x(1.218¹¹)

Year 12: x(1.218¹²) = 79,400

x(10.6602517) = 79,400

x = 79,400/10.6602517

x=7448.22939

x = $7448

Hope this helps!

6 0

1 year ago

A suit originally costing $240 is on sale for 25% off the original price. Sales tax is 7.5%. What is the final cost of the suit?

Finger [1]

$193.50

start by multiplying 240 by .25 (25%) to find out how much is 25% of 240. this equals 60.
then, subtract $60 from $240. equals 180.
next, to add the sales tax, multiply 180 by 0.075 (7.5%) this is $13.50.
lastly, add the tax, which is $13.50, to the suit's sale price, which is $180.
180+13.5= $193.50

5 0

2 years ago

Read 2 more answers

The use of mathematical methods to study the spread of contagious diseases goes back at least to some work by Daniel Bernoulli i

harina [27]

Answer:

a

$y(t) = y_o e^{\beta t}$

b

$x(t) = x_o e^{\frac{-\alpha y_o }{\beta }[e^{-\beta t} - 1] }$

c

$\lim_{t \to \infty} x(t) = x_oe^{\frac{-\alpha y_o}{\beta } }$

Step-by-step explanation:

From the question we are told that

$\frac{dy}{y} = -\beta dt$

Now integrating both sides

$ln y = \beta t + c$

Now taking the exponent of both sides

$y(t) = e^{\beta t + c}$

=> $y(t) = e^{\beta t} e^c$

Let $e^c = C$

So

$y(t) = C e^{\beta t}$

Now from the question we are told that

$y(0) = y_o$

Hence

$y(0) = y_o = Ce^{\beta * 0}$

=> $y_o = C$

So

$y(t) = y_o e^{\beta t}$

From the question we are told that

$\frac{dx}{dt} = -\alpha xy$

substituting for y

$\frac{dx}{dt} = - \alpha x(y_o e^{-\beta t })$

=> $\frac{dx}{x} = -\alpha y_oe^{-\beta t} dt$

Now integrating both sides

$lnx = \alpha \frac{y_o}{\beta } e^{-\beta t} + c$

Now taking the exponent of both sides

$x(t) = e^{\alpha \frac{y_o}{\beta } e^{-\beta t} + c}$

=> $x(t) = e^{\alpha \frac{y_o}{\beta } e^{-\beta t} } e^c$

Let $e^c = A$

=> $x(t) =K e^{\alpha \frac{y_o}{\beta } e^{-\beta t} }$

Now from the question we are told that

$x(0) = x_o$

So

$x(0)=x_o =K e^{\alpha \frac{y_o}{\beta } e^{-\beta * 0} }$

=> $x_o = K e^{\frac {\alpha y_o }{\beta } }$

divide both side by $(K * x_o)$

=> $K = x_o e^{\frac {\alpha y_o }{\beta } }$

So

$x(t) =x_o e^{\frac {-\alpha y_o }{\beta } } * e^{\alpha \frac{y_o}{\beta } e^{-\beta t} }$

=> $x(t)= x_o e^{\frac{-\alpha * y_o }{\beta} + \frac{\alpha y_o}{\beta } e^{-\beta t} }$

=> $x(t) = x_o e^{\frac{\alpha y_o }{\beta }[e^{-\beta t} - 1] }$

Generally as t tends to infinity , $e^{- \beta t}$ tends to zero

so

$\lim_{t \to \infty} x(t) = x_oe^{\frac{-\alpha y_o}{\beta } }$

5 0

3 years ago