We need to find a tree such that the angle of elevation from the end of the shadow to top of the tree is 40 degrees.
The length of the shadow is the adjacent side and is 35.
The height of the tree is the opposite side. Let it be x.
Tan ratio = opposite/adjacent
tan(40) = x/35
x = 35*tan(40) = 29.37
Answer: Height of the tree is 29 feet
Geometry ahh I wish I could help. :'(
9514 1404 393
Answer:
14. 53.1°
16. 253.7°
Step-by-step explanation:
14. The measure of angle L can be found from the cosine relation:
Cos = Adjacent/Hypotenuse
cos(L) = 9/15 = 3/5
L = arccos(3/5) = 53.1° . . . arc MK
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16. Arc MK is half of arc JK, so that arc is 106.3°. The long arc JPK is the difference between 360° and the measure of the short arc JK.
360° -106.3° = 253.7° . . . arc JPK
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With such a high mean an outlier that is of the value of ten would cause the mean of the data set to decrease.
