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horsena [70]
3 years ago
9

When sales representatives for a pharmaceutical company drive to​ out-of-town meetings that require an overnight​ stay, they rec

eive ​$125for lodging plus ​$0.80 per mile driven. How many miles did Joe drive if his company reimbursed him ​$301 for an overnight​ trip?
Mathematics
1 answer:
Andreas93 [3]3 years ago
8 0

Answer:

220 miles

Step-by-step explanation:

Joe got $301 for an overnight trip.

As the employees get $125 for lodging. The lodging expense will be subtracted from the total amount to get the amount for the miles he drove.

So,

Expense by company for miles driver = 301 - 125 = $176

So, Joe received $176 for miles driven

Now,

amount for one mile = $0.80

Miles driven in $176 = 176/0.80 = 220 miles

Joe drove 220 miles ..

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Answer:

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7 0
2 years ago
Answer with steps thnx
expeople1 [14]

Answer:

The area is 432cm squared.

Step-by-step explanation:

To find the area, first you split the figure into 2 rectangles.

The rectangle facing up would be 8cm by 30cm, and the rectangle pointing to the left would be 8cm by 24cm (because you subtract 8 by 32). Next, with those numbers, you can easily find the area. 8cm x 30cm equals to 240cm squared, and 8cm x 24cm equals to 192cm squared. Lastly, you add the both of the areas together, 240cm and 192cm, and you get 432cm squared.

6 0
4 years ago
True or false if you divide a number by two it's always even
Gnesinka [82]
False, ex: 18/2 = 9
false, ex: 18/2 = 9
8 0
3 years ago
Read 2 more answers
A bag contains 4 blue marbles and 2 yellow marbles. Two marbles are randomly chosen (the first marble is NOT replaced before dra
VMariaS [17]

Answer:

0.4 = 40% probability that both marbles are blue.

0.0667 = 6.67% probability that both marbles are yellow.

53.33% probability of one blue and then one yellow

If you are told that both selected marbles are the same color, 0.8571 = 85.71% probability that both are blue

Step-by-step explanation:

To solve this question, we need to understand conditional probability(for the final question) and the hypergeometric distribution(for the first three, because the balls are chosen without being replaced).

Hypergeometric distribution:

The probability of x sucesses is given by the following formula:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

In which:

x is the number of sucesses.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

What is the probability that both marbles are blue?

4 + 2 = 6 total marbles, which means that N = 6

4 blue, which means that k = 4

Sample of 2, which means that n = 2

This is P(X = 2). So

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

P(X = 2) = h(2,6,2,4) = \frac{C_{4,2}*C_{2,0}}{C_{6,2}} = 0.4

0.4 = 40% probability that both marbles are blue

What is the probability that both marbles are yellow?

4 + 2 = 6 total marbles, which means that N = 6

2 yellow, which means that k = 2

Sample of 2, which means that n = 2

This is P(X = 2). So

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

P(X = 2) = h(2,6,2,2) = \frac{C_{2,2}*C_{4,0}}{C_{6,2}} = 0.0667

0.0667 = 6.67% probability that both marbles are yellow.

What is the probability of one blue and then one yellow?

Total is 100%.

Can be:

Both blue(40%)

Both yellow(6.67%)

One blue and one yellow(x%). So

40 + 6.67 + x = 100

x = 100 - 46.67

x = 53.33

53.33% probability of one blue and then one yellow.

If you are told that both selected marbles are the same color, what is the probability that both are blue?

Conditional probability.

Event A: Both same color

Event B: Both blue

Probability of both being same color:

Both blue(40%)

Both yellow(6.67%)

This means that P(A) = 0.4 + 0.0667 = 0.4667

Probability of both being the same color and blue:

40% probability that both are blue, which means that P(A \cap B) = 0.4

Desired probability:

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.4}{0.4667} = 0.8571

If you are told that both selected marbles are the same color, 0.8571 = 85.71% probability that both are blue

8 0
3 years ago
How to write3.repeating 7 as a mixed number
ki77a [65]

Hey there! I'm happy to help!

Let's call our fraction x.

x=3.777......

We want to get rid of the repeating stuff. If we multiply our fraction by 10, we get 10x=37.7777.

We see that if we subtract x from 10x, the repeating numbers will be cancelled out. Let's do this.

10x=37.7777

-

x=3.77777

=

9x=34

We divide both sides by 9.

x=34/9=3 7/9.

Have a wonderful day! :D

6 0
3 years ago
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