Answer:
False. See te explanation an counter example below.
Step-by-step explanation:
For this case we need to find:
for all
and for
in the Markov Chain assumed. If we proof this then we have a Markov Chain
For example if we assume that
then we have this:

Because we can only have
if we have this:
, from definition given 
With
we have that 
So based on these conditions
would be 1 with probability 1/2 from the definition.
If we find a counter example when the probability is not satisfied we can proof that we don't have a Markov Chain.
Let's assume that
for this case in order to satisfy the definition then 
But on this case that means
and on this case the probability
, so we have a counter example and we have that:
for all
so then we can conclude that we don't have a Markov chain for this case.
Answer: Choice B) I and II only
The mean and median are considered measures of center as they represent the average of a data set. The average basically being a point that collectively speaks for all of the data. For example, if you have a group of basketball players whose heights range from 5'11" to 6'9", then there is no single height to report; however, we can compute the average to get a basic idea of the single height. The interquartile range (IQR) is a measure of variability or spread of the data. The higher the IQR, the more spread out the data is. Recall that 50% of the data is represented by the IQR and that IQR = Q3 - Q1 where Q1 and Q3 are the first and third quartiles respectively. So because the IQR is a measure of spread, it is not considered a center point.
Answer:
8y+5x
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Answer:
B. f(-4) = g(-4), and f(0) = g(0)
Step-by-step explanation:
We are given two functions that have been graphed already. The points on the coordinate plane where the curve of g(x) intercepts that of f(x), are the values of x for each function, that would give us the same output (y).
Thus, for f(x) intercepts g(x) at the point where x = -4, y = 4.
Also, f(x) and g(x) intercepts at the point where x = 0, y = 4.
Therefore, the correct answer is f(-4) = g(-4), and f(0) = g(0)
Answer:
8x !
Step-by-step explanation: