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2 years ago

R^2+7r+10/3 / 3-30/r2-5r-50

2 answers:

8 0

Multiply r^2+7r+10/3 by 3r-30/r^2-5r-50
=( r^2+7r+10)/3 (3r-30)/(r^2-5r-50) 
=(r+2)(r+5)/3 3(r+10)/ (r-10)(r+5) 
=3 (r+2)(r+5)(r+10)/3(r-10)(r+5) 
=(r+2)(r+10)/(r-10)

Simora [160]2 years ago

3 0

Answer:

umm i think its r+2

Step-by-step explanation:

((r²+7r+10)/3) × (3r-30)/(r²-5r=50)= Factoring the expression (r²+7r+10) we get (r+2)(r+5)

Then multiply it with the other numerator, we get = (r+2)(r+5)(3(r-10)

Then we factorise = (r²-5r-50) = (r+5)(r-10)

Multiplying it with the other denominator, we have; = 3(r+5)(r-10)

Therefore dividing (r+2)(r+5)(3(r-10)/(3(r+5)(r-10) we get; = r+2

Therefore, the correct answer is r+2 (NOT MY WORK) (YAY)

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A pole that is 2.5 m tall casts a shadow that is 1.47 m long. At the same time, a nearby tower casts a shadow that is 36.25 m lo

Roman55 [17]

The tower is 61.65 meters tall.

SOLUTION:

Given that, a pole that is 2.5 m tall casts a shadow that is 1.47 m long.

At the same time, a nearby tower casts a shadow that is 36.25 m long.

We have to find height of the tower.

Now, we know that,

$2.5 \mathrm{m} \text { tall } \rightarrow 1.47 \text { long shadow }$

Then, (let it be) n meter tall $\rightarrow$ 36.25 long shadow

So, by cross multiplication method,

$\Rightarrow \frac{2.5}{1.47}=\frac{n}{36.25}$

This can be written as,

$\Rightarrow 36.25 \times 2.5=1.47 \times n \rightarrow 1.47 n=90.625 \rightarrow n=61.649 \rightarrow n=61.65 \text{ m}$

Cross multiplications steps: (To find Single Variable)

Multiply the numerator of the left-hand fraction by the denominator of the right-hand fraction.
Multiply the numerator of the right-hand fraction by the denominator of the left-hand fraction.
Set the two products equal to each other.
Solve for the variable.

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3 years ago

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Answer:

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Step-by-step explanation:

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3 years ago

Which angle measures create a triangle with three different side lengths?

dedylja [7]

Answer:

Step-by-step explanation:

For 3 different side lengths, you need 3 different angles. That eliminates A, B and D.

A: In the case of A, The angles do not add up to 180 so this is not possible. Even if it was, the angles are all the same and the side lengths would be as well.

B: Two angles are the same, therefore, 2 sides will be the same, even though the two sides added together will be larger than the side opposite.

D: Two angles are the same. The angles add to 180. The triangle will have 2 equal sides.

C: Answer. The three given angles add to 180. They are different. Unless the side opposite 93 exceeds the length of the other 2 sides, this forms a triangle with 3 different sides. Using other methods to calculate the answer the other 2 sides do exceed the the base length so everything is fine.

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