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aliina [53]
3 years ago
11

Ravi buys candy that costs $4 per pound. He will buy at most 10 pounds of candy what are the possible amounts he will spend on c

andy?
Mathematics
2 answers:
Damm [24]3 years ago
8 0

Answer:

$40

Step-by-step explanation:

$4x10

Sloan [31]3 years ago
5 0
The cost will be from either 4 dollars to 40 dollars
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a triangle has area 49.5 cm^2. if the base of the triangle is 9 cm, what is the height of the triangle
Anika [276]
Area of a triangle = (height * base ) / 2

height = (Area * 2) / base
height = (49.5 * 2) / 9
height = 99 / 9
height = 10 cm²
3 0
3 years ago
Jose estimates that if he leaves his car parked outside his office all day on a weekday, the chance that he will get a parking t
Elan Coil [88]

Answer:

Therefore, the probability is P=0.74.

Step-by-step explanation:

We know that Jose estimates that if he leaves his car parked outside his office all day on a weekday, the chance that he will get a parking ticket is 26%.  

Therefore the probability that he will get a parking ticket is P1=0.26.

We calculate the probability that he will not get a parking ticket.

We get:

P=1-P1

P=1-0.26

P=0.74

Therefore, the probability is P=0.74.

8 0
3 years ago
Solve for x: 4/x+4/x2-9=3/x-3
anzhelika [568]

Answer:

x =1/12(1-√(97) )

Step-by-step explanation:

4 0
3 years ago
Consider the following system of equations:
Delicious77 [7]

Answer:

The system has infinitely solutions

Step-by-step explanation:

we have

-\frac{1}{3}x^{2}=-\frac{5}{6}+\frac{1}{3}y^{2}

\frac{1}{3}x^{2}+\frac{1}{3}y^{2}=\frac{5}{6}

Multiply by 3 both sides

x^{2}+y^{2}=\frac{5}{2} ----> equation A

The equation A is a circle centered at origin with radius r=\sqrt{5/2}\ units

and

5y^{2} =\frac{25}{2}-5x^{2}

5x^{2}+5y^{2} =\frac{25}{2}

Divide by 5 both sides

x^{2}+y^{2} =\frac{5}{2} ----> equation B

The equation B is a circle centered at origin with radius r=\sqrt{5/2}\ units

Equation A and Equation B are the same

Therefore

The system has infinitely solutions

7 0
3 years ago
Read 2 more answers
Can someone please help me with this problem? You need to find the value of x and y by using the strategy of ELIMINATION. Please
Setler [38]

Answer:

x = 136/35; y = -⁹/₁₀

Step-by-step explanation:

(1)         7x + 8y = 20

(2)        7x – 2y = 29       Subtract (2) from (1)

                  10y =  -9        Divide each side by 10

(3)                 y =  -⁹/₁₀     Substitute (3) into (1)

      7x - 2(-⁹/₁₀) = 29

      7x + 18/10  = 29                       Subtract 18/10 from each side

      7x              =      29 - 18/10

      7x              = (290 - 18)/10

      7x              =          272/10        Divide each side by 7

        x              =           272/70

        x              =           136/35

x = 136/35; y = -⁹/₁₀

Check:

(1) 7(136/35) + 8(-⁹/₁₀) = 20

      136/5    -   72/10 = 20

      136/5    -   36/5  = 20

                      100/5  = 20

                       20      = 20

(2) 7(136/35) – 2(-⁹/₁₀)  = 29

       136/5    +    18/10 = 29

       136/5    +      ⁹/₅    = 29

                        145/5  = 29

                        29       = 29

5 0
3 years ago
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