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Ipatiy [6.2K]
2 years ago
14

What is the y-intercept of the function, represented by the table of values below? x: -2,1,2,4,7 y: 14,8,6,2,-4

Mathematics
1 answer:
anastassius [24]2 years ago
7 0

Answer:

The y-intercept is at y = 10.

Step-by-step explanation:

It will be between y = 14 and y = 7 because the corresponding x values are -2 and 1.

An increase of 3 units of x  gives a decrease of 6 units of y fro the above values.

Then an increase of 1 ( 1 to 2) in x gives decrease in y of 2 (8 to 6). The other values show the same pattern.

So very unit increase in x,  the y values change by -2.

So  from x = -2 to 0 is +2 units for x and this will be -4 units for y  so the y-intercept ( when x = 0) will be at y = 14-4 = 10

y-intercept  is (0,10).


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3 years ago
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On any given day, mail gets delivered by either Alice or Bob. If Alice delivers it, which happens with probability 1/4 , she doe
Troyanec [42]

Answer:

(a) The value of fₓ (9.5) is 0.125.

(b) The value of fₓ (10.5) is 0.50.

Step-by-step explanation:

Let <em>X</em> denote delivery time of the mail delivered by Alice and <em>Y</em> denote delivery time of the mail delivered by Bob.

It i provided that:

X\sim U(9, 11)\\Y\sim U(10, 12)

The probability that Alice delivers the mail is, <em>p</em> = 1/4.

The probability that Bob delivers the mail is, <em>q</em> = 3/4.

The probability density function of a Uniform distribution with parameters [<em>a</em>, <em>b</em>] is:

f(x)=\left \{ {{\frac{1}{b-a};\ a, b>0} \atop {0;\ otherwise}} \right.

The probability density function of the delivery time of Alice is:

f(X_{A})=\left \{ {{\frac{1}{b-a}=\frac{1}{2};\ [a, b]=[9, 11]} \atop {0;\ otherwise}} \right.

The probability density function of the delivery time of Bob is:

f(X_{B})=\left \{ {{\frac{1}{b-a}=\frac{1}{2};\ [a, b]=[10, 12]} \atop {0;\ otherwise}} \right.

(a)

Compute the value of fₓ (9.5) as follows:

For delivery time 9.5, only Alice can do the delivery because Bob delivers the mail in the time interval 10 to 12.

The value of fₓ (9.5) is:

f_{X}(9.5)=p.f(X_{A})+q.f(X_B})\\=(\frac{1}{4}\times \frac{1}{2})+(\frac{3}{4}\times0)\\=\frac{1}{8}\\=0.125

Thus, the value of fₓ (9.5) is 0.125.

(b)

Compute the value of fₓ (10.5) as follows:

For delivery time 10.5, both Alice and Bob can do the delivery because Alice's delivery time is in the interval 9 to 11 and that of Bob's is in the time interval 10 to 12.

The value of fₓ (10.5) is:

f_{X}(10.5)=p.f(X_{A})+q.f(X_B})\\=(\frac{1}{4}\times \frac{1}{2})+(\frac{3}{4}\times\frac{1}{2})\\=\frac{1}{8}+\frac{3}{8}\\=0.50

Thus, the value of fₓ (10.5) is 0.50.

5 0
3 years ago
digit at tens place of two digit number is twice the digit at units place .if sum of this number and the no.formed by reversing
Dima020 [189]
Let the number be     xy ,

xy = 10x + y.   when reversed = yx = 10y + x

x = 2y          ........(a)

10x + y + 10y + x = 66.........(b)

10(2y) + y + 10y + 2y = 66

20y + y + 10y + 2y = 66

33y = 66

y = 66/33

y = 2

x = 2y = 2*2 = 4

Recall the original number is xy =     42.
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3 i think here is the brainly link where i found tht brainly.com/question/472442     if i helped would you mark me brainiest if i helped?
7 0
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