The quadratic has one root with multiplicity 2 if the discriminant is 0, which is
(That is, for a quadratic 
, the discriminant is 
.)
Set the discriminant equal to 0 and solve for 
:
The answer to the question is in the picture.
There are two probabilities of the solution. First if 80° acts as one of the leg angles, second if 80° acts as the vertex angle.
FIRST PROBABILITY
If 80° is one of the leg angles, then the other angle would be 80° too, because iscosceles has two congruent angles on the leg.
Find the vertex angle
the sum of interior angles in a triangle is 180°
vertex angle + angle on the leg + angle on the leg = 180°
vertex angle + 80° + 80° = 180°
vertex angle + 160° = 180°
vertex angle = 180° - 160°
vertex angle = 20°
The interior angles are 80°,80°,20°
SECOND PROBABILITY
If 80° is the vertex angle, we should find the value of the two leg angles. The two legs has congruent angles.
Find the leg angles
the sum of interior angles in a triangle is 180°
leg angle + leg angle + vertex angle = 180°
2 × leg angle + vertex angle = 180°
2 × leg angle + 80° = 180°
2 × leg angle = 180° - 80°
2 × leg angle = 100°
leg angle = 50°
The interior angles are 80°, 50°, 50°
Answer:
f(x) = 3x^2 - 12x - 36.
Step-by-step explanation:
f(x) =3 /2(x - 2)^2 - 24
f(x) = 3/2 (x^2 - 4x + 4) - 24
f(x) = 3/2 x^2 - 6x + 6 - 24
f(x) = 3/2 x^2 - 6x - 18
Multiply through by 2:
f(x) = 3x^2 - 12x - 36.
It would be no, because there is a lot of variability in the computer science book. Hope I help!
