The value of the <em>a, </em>in the provided quadratic equation for which Nancy found one solution as x=1 is 9.
<h3>What is the solution of equation?</h3>
The solution of the quadratic equation is the solution of the variable of the equation, for which the equation satisfies.
Nancy found that x=1 is one solution to the quadratic equation. The quadratic equation is,

For this equation, one solution is <em>x</em>=1. Put this value in the above equation to get the value of <em>a,</em>

Thus, the value of the <em>a, </em>in the provided quadratic equation for which Nancy found one solution as x=1 is 9.
Learn more about the solution of the equation here;
brainly.com/question/21283540
P=45
How do I Know that?
<em>I added 35+100 and that equal to 180, so Then I subtracted 180-135 and that gave me 45. So P=35. Add all of them up to see if it = 180 and if it does, then your answer is correct. remeber 3 angles of a triangle =180.</em>
Using proportions, it is found that the amount of the novel she would have read is:
D. 14/15.
<h3>What is a proportion?</h3>
A proportion is a fraction of a total amount, and the measures are related using a rule of three. Due to this, relations between variables, either direct or inverse proportional, can be built to find the desired measures in the problem.
She has finished 5/6 of the novel, and will have read more 1/10 in the next two days, hence the total amount read is given by:

Hence option D is correct.
More can be learned about proportions at brainly.com/question/24372153
#SPJ1
Answer:
35 mililiters
Step-by-step explanation:
Given

Required
Accumulated amount from t = 0 to 2
This implies that, we substitute the values of t from 0 to 2 in the function



The accumulated sand (r) is:


