The weights of a small box of healthy oats are normally distributed with a mean of 8.9 oz and a standard deviation of 0.1 oz. Fi
nd the probability that a randomly chosen box of healthy oats weighs more than 8.8 oz. Express the probability as a decimal.
2 answers:
Answer:
) Compute the sample mean x and the sample standard deviation s.
Do NOT use a computer. You may only use +, –, ×, ÷, and on a calculator.
Show ALL work.
9
143.1
9
15.5 16.2 16.1 15.8 15.6 16.0 15.8 15.9 16.2 = = = ∑ + + + + + + + +
n
x
x
i
= 15.9.
x x 2 x x − x ( ) 2
x − x
15.5
16.2
16.1
15.8
15.6
16.0
15.8
15.9
16.2
240.25
262.44
259.21
249.64
243.36
256.00
249.64
252.81
262.44
OR
15.5
16.2
Step-by-step explanation:
Answer:
The answer is 0.84.
Step-by-step explanation:
I solved it and got it all correct.
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Answer:
k = 2.5
Step-by-step explanation:
2.5 (4k+2) = 12k
10k + 5 = 12k
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5 = 2k
5/2
2.5
Answer:
There are 36 possibilities per character (26 lower case letters + 10 numbers), so the total number of permutations are 36^4 = 1,679,616
Step-by-step explanation:
