The weights of a small box of healthy oats are normally distributed with a mean of 8.9 oz and a standard deviation of 0.1 oz. Fi
nd the probability that a randomly chosen box of healthy oats weighs more than 8.8 oz. Express the probability as a decimal.
2 answers:
Answer:
) Compute the sample mean x and the sample standard deviation s.
Do NOT use a computer. You may only use +, –, ×, ÷, and on a calculator.
Show ALL work.
9
143.1
9
15.5 16.2 16.1 15.8 15.6 16.0 15.8 15.9 16.2 = = = ∑ + + + + + + + +
n
x
x
i
= 15.9.
x x 2 x x − x ( ) 2
x − x
15.5
16.2
16.1
15.8
15.6
16.0
15.8
15.9
16.2
240.25
262.44
259.21
249.64
243.36
256.00
249.64
252.81
262.44
OR
15.5
16.2
Step-by-step explanation:
Answer:
The answer is 0.84.
Step-by-step explanation:
I solved it and got it all correct.
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0.5
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Answer:
9.07 and 7.77 respectively.
Step-by-step explanation:
To determine the upper control limit, add 0.65 lb to 8.42 lb, obtaining 9.07 lb.
To determine the lower one, subtract 0.65 lb from 8.42 lb, obtaining 7.77 lb.
Area is just height times width so if it’s a square all sides are equal so you do 3 2/7 time 3 2/7 and get 10.796 in^2
