Question

The inverse variation equation shows the relationship between wavelength in meters, x, and frequency, y

Answer 1

Answer:

B

Step-by-step explanation:

Answer 2

We have been given that the inverse variation $y=\frac{3\times 10^8}{x}$ shows the relationship between wavelength in meters, x, and frequency, y. We are asked to find the wavelength for radio waves with frequency $3\times 10^9$.

To find the required wavelength, we substitute $y=3\times 10^9$ in our given equation and solve for x as:

$3\times 10^9=\frac{3\times 10^8}{x}$

$x=\frac{3\times 10^8}{3\times 10^9}$

We can see that both numerator and denominator has 3, so we can cancel it out.

$x=\frac{1\times 10^8}{1\times 10^9}$

Using quotient rule of exponents $\frac{a^m}{a^n}=a^{m-n}$, we will get:

$x=1\times 10^{8-9}$

$x=1\times 10^{-1}$

Therefore, the wavelength for radio waves would be $1\times 10^{-1}$ meters and option B is the correct choice.