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ella [17]
3 years ago
5

Which equation describes the circle having center point (3,7) and the radius r=4 in Standard form

Mathematics
1 answer:
Annette [7]3 years ago
6 0

The equation of circle in standard form is (x - 3)^2 + (y - 7)^2 = 16

<h3><u>Solution:</u></h3>

Given that circle having center point (3,7) and the radius r = 4

To find: equation of circle in standard form

<em><u>The equation of circle is given as:</u></em>

(x - h)^2 + (y - k)^2 = r^2

Where center (h,k) and radius r units

Given that center point (h , k) = (3, 7) and radius r = 4 units

Substituting the values in above equation of circle,

(x - 3)^2 + (y - 7)^2 = 4^2\\\\(x - 3)^2 + (y - 7)^2 = 16

Thus the equation of circle in standard form is (x - 3)^2 + (y - 7)^2 = 16

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Answer: Kate = 40/3  Her father = 50

Step-by-step explanation:

Let Kate's age in the present be K

And Kate's father's age in the present be F

3(K+5) = F+5

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Rearrange the first equation to get

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Substitute that into the second question

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8 0
2 years ago
Find the values for a and b that would make the equality true.
Crank

Answer:

a = - 4, b = 5

Step-by-step explanation:

Expand the left side and compare the coefficients of like terms on the right side.

- 3(2x² + ax + b)

= - 6x² - 3ax - 3b

Comparing like terms with - 6x² + 12x - 15

x - term → - 3a = 12 ( divide both sides by - 3 )

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6 0
3 years ago
(a^(2)-4ac+3bc)/(a^(2)-ab+bc-ac)+(a+3b)/(b-a)+(a+2c)/(a-c)
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Answer:

The answer is −a^4 + 5a^3b + 2a^3c − 4a^2b^2 − 10a^2bc − a^2c^2 + 8ab^2c + 5abc^2 − 4b^2c^2  / −a^4 + 2a^3b + 2a^3c − a^2b^2 − 4a^2bc − a^2c^2 + 2ab^2c + 2abc^2 − b^2c^2

Step-by-step explanation:

This the equation being simplified

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3 years ago
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Step-by-step explanation:

Given that:

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This means that in one hour 7/18 of the distance is covered between two ports.

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