Question

Which equation describes the circle having center point (3,7) and the radius r=4 in Standard form

Answer 1

The equation of circle in standard form is $(x - 3)^2 + (y - 7)^2 = 16$

Solution:

Given that circle having center point (3,7) and the radius r = 4

To find: equation of circle in standard form

The equation of circle is given as:

$(x - h)^2 + (y - k)^2 = r^2$

Where center (h,k) and radius r units

Given that center point (h , k) = (3, 7) and radius r = 4 units

Substituting the values in above equation of circle,

$(x - 3)^2 + (y - 7)^2 = 4^2\\\\(x - 3)^2 + (y - 7)^2 = 16$

Thus the equation of circle in standard form is $(x - 3)^2 + (y - 7)^2 = 16$