Answer:
(0, -10)
Step-by-step explanation:
If you add both together from x - y, each add up to their own value. For example, -5, and -9 would be -14. It's quite simple. I hope this helps. I'm sorry if this is not what you are looking for.
Answer:
v > -21
Step-by-step explanation:
-1/3v - 2 < 5
add 2
-1/3v < 7
multiply by -3
(if negative, switch sign)
v > -21
Answer:
(a) x = -2y
(c) 3x - 2y = 0
Step-by-step explanation:
You can tell if an equation is a direct variation equation if it can be written in the format y = kx.
Note that there is no addition and subtraction in this equation.
Let's put these equations in the form y = kx.
(a) x = -2y
- y = x/-2 → y = -1/2x
- This is equivalent to multiplying x by -1/2, so this is an example of direct variation.
(b) x + 2y = 12
- 2y = 12 - x
- y = 6 - 1/2x
- This is not in the form y = kx since we are adding 6 to -1/2x. Therefore, this is <u>NOT</u> an example of direct variation.
(c) 3x - 2y = 0
- -2y = -3x
- y = 3/2x
- This follows the format of y = kx, so it is an example of direct variation.
(d) 5x² + y = 0
- y = -5x²
- This is not in the form of y = kx, so it is <u>NOT</u> an example of direct variation.
(e) y = 0.3x + 1.6
- 1.6 is being added to 0.3x, so it is <u>NOT</u> an example of direct variation.
(f) y - 2 = x
- y = x + 2
- 2 is being added to x, so it is <u>NOT</u> an example of direct variation.
The following equations are examples of direct variation:
Answer:
it should be the negative repirocal of -2 so 1/2
The question is incomplete. Below you will find the missing graph.
The lowest value of the range of the function shown on graph is (B) -2.
Graph is the pictorial representation of the function or mathematical relation.
The lowest value of the graph is the value of y when 
gives the least value.
From the given graph we can clearly see that at 
the graph of the given function approaches the least value which is -2.
So the lowest value of the range of the function shown on the graph is -2.
Hence the correct option is (B).
Learn more about Graph here -
brainly.com/question/4025726
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