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3 years ago

What is the answer to number 5. Given BD=24 and PC=13, find PB

Mathematics

2 answers:

irakobra [83]3 years ago

7 0

The second one because of the points and it would need to be pc=13

Umnica [9.8K]3 years ago

5 0

Well first, we know BD which is equal to 24 is bisected by QC. Thus BC is 12 units long. Now that we know 2 sides of the triangle PBC, we can find the third missing side, PB, using the Pythagorean Theorem:

BC^2 + PB^2 = PC^2

12^2 + PB^2 = 13^2

144 + PB^2 = 169

PB^2 = 25

PB = 5

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A standard deck of 52 playing cards contains 13 cards in each of four suits: hearts, diamonds, clubs, and spades.

N76 [4]

Answer: a) 1%

<u>Step-by-step explanation:</u>

1st draw and 2nd draw and 3rd draw and 4th draw

$\dfrac{13}{52}$ x $\dfrac{12}{51}$ x $\dfrac{11}{50}$ x $\dfrac{39}{49}$ = $\dfrac{66,924}{6,497,400}$

= 0.01

= 1%

4 0

3 years ago

Read 2 more answers

The perimeter of an equilateral triangle is 77 inches more than the perimeter of a square, and the side of the triangle is 55 i

miv72 [106K]

Answer:

143 inches

Step-by-step explanation:

Let the triangle be $s$ inches long.

Then the perimeter of the equilateral triangle will be $s+s+s=3s$ inches.

Let the length of the square also be $l$ inches.

Then the perimeter is $4l$

It was given that the perimeter of the equilateral triangle is 77 inches more than the perimeter of the square.

So we can write the relation

$3s=4l+77$

$\Rightarrow 3s-4l=77..eqn1$

Also, the side of the triangle is 55 inches longer than the side of the square.

So we write $s=l+55$ or $l=s-55...eqn2$

We put equation (2) into equation (1) to get;

$3s-4(s-55)=77$

We expand the bracket to get;

$3s-4s+220=77$

$3s-4s=77-220$

$-s=-143$

$s=143$

Hence the triangle is 143 inches long.

8 0

3 years ago

W much

Bezzdna [24]

Jerome bought C. $4\frac{7}{8}$ pounds of candy.

Step-by-step explanation:

Step 1:

First, we must convert the mixed fractions into improper fractions. To do that we multiply the whole number with the denominator and add with it the numerator while the denominator remains the same.

To convert this fraction $1\frac{1}{2} = \frac{(1)(2)+1}{2} =\frac{3}{2} .$

To convert this fraction $2\frac{3}{4} = \frac{(2)(4)+3}{4} =\frac{11}{4} .$

So Jerome bought $\frac{3}{2}$ pounds of jelly beans, $\frac{5}{8}$ pounds of gumballs and $\frac{11}{4}$ pounds of chocolate.

Step 2:

We add all the values to determine the total candy bought.

$\frac{3}{2} +\frac{5}{8} + \frac{11}{4} = \frac{(4(3)+1(5)+2(11))}{8} .$

$\frac{(4(3)+1(5)+2(11))}{8} = \frac{39}{8} .$

$\frac{39}{8}$ can also be written as $4\frac{7}{8}$ .

So Jerome bought $4\frac{7}{8}$ pounds of candy which is option C.

6 0

4 years ago

In a lab experiment, the decay of a radioactive isotope is being observed. At the beginning of the first day of the experiment t

GaryK [48]

Using an exponential function, it is found that the mass of the radioactive sample at the beginning of the 13th day of the experiment was of 169.1 mg.

<h3>What is an exponential function?</h3>

A decaying exponential function is modeled by:

$A(t) = A(0)(1 - r)^t$

In which:

A(0) is the initial value.

r is the decay rate, as a decimal.

At the beginning of the first day of the experiment the mass of the substance was 500 grams and mass was decreasing by 8% per day, hence A(0) = 500, r = 0.08, and the equation is given by:

$A(t) = A(0)(1 - r)^t$

$A(t) = 500(1 - 0.08)^t$

$A(t) = 500(0.92)^t$

At the 13th day, the mass is given by:

$A(13) = 500(0.92)^{13} = 169.1$

More can be learned about exponential functions at brainly.com/question/25537936

5 0

2 years ago

A lawn in the shape of a trapezoid has an area of 1,800 square meters. The length of one base is 50 meters, and the length of th

Alona [7]

9514 1404 393

Answer:

40 m

Step-by-step explanation:

The area is given by the formula ...

A = 1/2(b1 +b2)h

Using the given values, we can find h to be ...

1800 = 1/2(50 +40)h

3600 = 90h . . . . . . . . . multiply by 2

40 = h . . . . . . . . . . . divide by 90

The width of the lawn is 40 meters.

6 0

3 years ago