Complete the square for x and y.
7x^2 + 3y^2 - 28x - 12y = -19
7x^2 - 28x + 3y^2 - 12y = -19
7(x^2 - 4x) + 3(y^2 - 4y) = -19
7(x^2 - 4x + 4) + 3(y^2 - 4y + 4) = -19 + 28 + 12
7(x - 2)^2 + 3(y - 2)^2 = 21
Answer:
Step-by-step explanation:
B. -3
Hope that helps!
Answer:
where is this from
Step-by-step explanation:
Answer: 2((x+y)-21)
Calculation/Explanation:
Twice the sum of x and y decreased by 21 means that you must add x and y first before decreasing by 21. The last step is to double the whole equation that we just performed.
Answer:
the answer to this problem would be 8.