Use the rules of logarithms and the rules of exponents.
... ln(ab) = ln(a) + ln(b)
... e^ln(a) = a
... (a^b)·(a^c) = a^(b+c)
_____
1) Use the second rule and take the antilog.
... e^ln(x) = x = e^(5.6 + ln(7.5))
... x = (e^5.6)·(e^ln(7.5)) . . . . . . use the rule of exponents
... x = 7.5·e^5.6 . . . . . . . . . . . . use the second rule of logarithms
... x ≈ 2028.2 . . . . . . . . . . . . . use your calculator (could do this after the 1st step)
2) Similar to the previous problem, except base-10 logs are involved.
... x = 10^(5.6 -log(7.5)) . . . . . take the antilog. Could evaluate now.
... = (1/7.5)·10^5.6 . . . . . . . . . . of course, 10^(-log(7.5)) = 7.5^-1 = 1/7.5
... x ≈ 53,080.96
The answer is a=7 because you have to do 7-6 which equals to 2 which a=7 is the right answer
Answer:
1.25b when b < 12 , 1b & then 0.75 b when b <u>> </u>12
Step-by-step explanation:
- Price for b bagels = Price x Quantity
* Less than 12 bagels bought, cost $1.25 per bagel
So, price for b bagels, when (b < 12) = 1.25b
* 12 or more than 12 bagels bought, cost $1 upto first 12 bagels & 0.75b on each additional bagel
So, price for b bagels, when (b = 12) = b
So, price for b bagels, when (b > 12) = b + 0.75b' , where b' denotes extra b beyond 12
Answer:
f(6) = -14
Step-by-step explanation:
x = -6
f(x) = x^2/3 - 2
f(-6) = (-6)^2/3 -2 Replace x with the given number
= -36/3 - 2 Simplify -6 to the power of 2
= - 12 - 2 Divide -36 by 3
f(6) = - 14 Subtract -2 from -12
