Answer:
V₂ = 252 cm³
Step-by-step explanation:
Charles's law = If the pressure is held constant, the volume of a gas varies directly with the temperature measured on the Kelvin scale.
Mathematically, ![V=kT](https://tex.z-dn.net/?f=V%3DkT)
![\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}](https://tex.z-dn.net/?f=%5Cdfrac%7BV_1%7D%7BT_1%7D%3D%5Cdfrac%7BV_2%7D%7BT_2%7D)
We have, V₁ = 192 cm³, T₁ = 112 K, T₂ = 147 cm³, V₂ = ?
Using the above relation of Charles's law :
![V_2=\dfrac{V_1T_2}{T_1}\\\\V_2=\dfrac{192\times 147}{112}\\\\V_2=252\ cm^3](https://tex.z-dn.net/?f=V_2%3D%5Cdfrac%7BV_1T_2%7D%7BT_1%7D%5C%5C%5C%5CV_2%3D%5Cdfrac%7B192%5Ctimes%20147%7D%7B112%7D%5C%5C%5C%5CV_2%3D252%5C%20cm%5E3)
So, the new temperature is 252 cm³.
8n>64
Divide both sides by 8, and you get
n>8
The slope of the line is -3/4, so the answer is B
Answer:
C. 5
Step-by-step explanation:
Use the Distance Formula.
Substitute the values of x1 , y1 , x2 , and y2 .
|AB|² =|(1--2)²+(10-6)²|
|AB|² = |9+16|
|AB| = √ 25
|AB| =5