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serg [7]
4 years ago
10

The difference between two positive integers is 54. One integer is three times as great as the other. Find the integer

Mathematics
1 answer:
sveta [45]4 years ago
7 0
The answer is 27
27+54=81 and 27x3= 81
:)
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16 and 17 please I don’t know if it’s the distance formula
Trava [24]

Answer:

#16 = (0, -10)

#17 = (-18, -3)

Step-by-step explanation:

U wouldn't use the distance formula, you would need to use the Midpoint Formula, which is, M = (x1 + x2 / 2, y1 + y2 / 2). For #16, you plug in (4, -5) for M and 8 for x1 and 0 for y1, so the equation should look like this : (4, -5) = (8 + x2 / 2, 0 + y2 / 2). Then separate the equation to make it easier: 4 = 8 + x2 / 2 and the second equation : -5 = 0 + y2 / 2. So let's do the 1st equation, the first step would be to multiply the 2 to both sides. So the equation should look like this, 8 = 8 + x. Then subtract the 8 from both sides and you get 0 as your x. Now moving on to the 2nd equation, you multiply the 2 to both sides, and you get, -10 = 0 + y, as your equation, but since 0 won't affect it, -10 should be your y. Then just use these steps to solve #17, and your answer should be (-18, -3).

6 0
3 years ago
Equivalent to (6 + y) × 5?
Sergeeva-Olga [200]
The answer is:
It’s equivalent to 30+5y
6 0
3 years ago
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13 + 11s = -15 + 8s − 20
koban [17]

<em>Answer,</em>

<em><u>S = -16</u></em>

<em>Explanation,</em>

<em><u>Step 1: Simplify both sides of the equation.</u></em>

<em>13 + 11s = − 15 + 8s − 20</em>

<em>13 + 11s = − 15 + 8s + − 20</em>

<em>11s + 13 = (8s) + (</em><em><u>− 15</u></em><em> + </em><em><u>− 20</u></em><em>) </em><em>(Combine Like Terms)</em>

<em>11s + 13 = 8s + − 35</em>

<em>11s + 13 = 8s − 35</em>

<em><u>Step 2: Subtract 8s from both sides.</u></em>

<em>11s + 13 − 8s = 8s − 35 − 8s</em>

<em>3s + 13 = − 35</em>

<em>Step 3: Subtract 13 from both sides.</em>

<em>3s + 13 − 13 = − 35 − 13</em>

<em>3s = − 48</em>

<em><u>Step 4: Divide both sides by 3.</u></em>

<em>3s/3 = −48/3</em>

<em>s = -16</em>


<u><em>Hope this helps :-)</em></u>


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3 years ago
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marishachu [46]

Answer:

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Step-by-step explanation:

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3 years ago
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Rise over run would be a thing to start with since you use graphs<span />
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