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Nataliya [291]
3 years ago
12

Let f(x)=3x-2 and g(x)=x^2+4 find f(g(12)

Mathematics
1 answer:
skad [1K]3 years ago
6 0

Answer:

442

Step-by-step explanation:

Find g(12) first.

12^2 + 4 = 144 + 4 = 148.

Now find f(148).

(3 x 148) -2 = 444-2 = 442.

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A candle maker has 4 1/2 pounds of clear wax. He wants to cut the wax into pieces that are 2/3 pound each. How many 2/3 pound pi
prisoha [69]

Answer:

a)  10  pieces of  2/3 pound  can be made.

b) 0.54 pounds of wax is left over.

Step-by-step explanation:

Total amount of clear wax available =  4\frac{1}{2}  = \frac{9}{2} pounds

So, the maker has in total 4.5 pounds of wax

Now, The weight of each piece = \frac{2}{3}  = 0.66  pounds

To find the number of pieces that can be made out of 4.5 pounds of wax,

let that number = n

So, n = \frac{\textrm{Total weight of the clear wax}}{\textrm{Weight of each wax}}

or, n = n = \frac{4.5}{0.66}  = 6.81

So, nearly 6 pieces can be made completely out of the clear wax

Left over amount of wax  = Total weight -  Weights of the pieces made

                                            =  4.5- 6(0.66)

                                            = 0.54 pounds

Hence, 0.54 pounds of wax is left over

8 0
3 years ago
What is the area of the circle?
Bumek [7]

Answer:

363

Step-by-step explanation:

Formula for area of a circle

A = πr^2

Where r = radius

The circle has a given radius of 11

To find the area of the circle we simply substitute r in the formula with the value of the radius (11)

( Also note that the question says to use 3 for π )

A = πr^2

π = 3

r = 11

Substitute values in formula

A = (3)(11)^2

11^2 = 121

A = 121(3)

121(3) = 363

A = 363

8 0
3 years ago
Read 2 more answers
Please help me!<br><br> Solve for x<br><br> 4−(2x+4)=5
Helga [31]
<span>4−(2x+4)=5
4 - 2x - 4 = 5
  -2x = 5
     x = -5/2
     x = - 2.5</span>
5 0
3 years ago
Read 2 more answers
state domain and range, intercepts, relative max and relative mins points and values, intervals of increase and decrease, interv
Anarel [89]

The domain of the graph is -∝ < x < ∝ and the range of the graph is -∝ < y < ∝. Also, the graph has no axis of symmetry

<h3>The domain and range of the graph</h3>

From the graph, we can see that the x values extend indefinitely

So, the domain of the graph is -∝ < x < ∝

From the graph, we can see that the y values extend indefinitely

So, the range of the graph is -∝ < y < ∝

<h3>The intercepts</h3>

This is where the graph crosses the axes

So, we have the intercepts to be

  • x-intercept = -4, -2 and 2
  • y-intercept = -9

<h3>Relative max and relative mins points and values, </h3>

The graph has a relative maximum at (3, 3) and the relative minimum are (0.5, 10)

<h3>Intervals of increase and decrease, </h3>

There are the intervals where the function increases and decreases

So, we have the intervals to be

  • Increasing interval: (0.5, ∝) and (-∝, -3)
  • Decreasing interval: (-3, 0.5)

<h3>Intervals of positive and negative,</h3>

There are the intervals where the function is positive and negative

So, we have the intervals to be

  • Positive interval: (-4, -2) and (2, ∝)
  • Negative interval: (-∝, -4) and (-2, 2)

<h3>The symmetry</h3>

This is the line that divides the graph equal part

In this case, the graph has no axis of symmetry

<h3>The end behavior</h3>

Using the intervals where the function is positive and negative, the end behavior is

  • As x ⇒ ∝, f(x) ⇒ +∝
  • As x ⇒ -∝, f(x) ⇒ -∝

Read more about functions at:

brainly.com/question/3951754

#SPJ1

3 0
2 years ago
3,4,4,5,5,6,6,6,6,7,9,12,14,15 Min: Q1: Med: Q3: Max:
kolezko [41]

Answer:

Median ( Q2) = 6

Q1 ( lower quartile) = 4.5

Q3 ( upper quaartile) = 10.5

Step-by-step explanation:

<u>3,4,4,5,5,6,  </u>6,6  ,<u>6,7,9,12,14,15</u>

6,6 is the median but we only need I median. So 6 + 6 = 12, 12 divided 2 = 6.

3,4,<u>4,5,</u>5,6,  is the Q1 ( lower quartile ) and median of Q1, is 4,5. 4 + 5 = 9. 9 divided 2 = 4.5

6,7,<u>9,12,</u>14,15  is Q3 ( upper quartile) 9,12 is median but we only need one. So 9 + 12 =21. 21 divided 2 = 10.5

5 0
2 years ago
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