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sesenic [268]
3 years ago
10

Which of the following are accepted without proof on a logical system?

Mathematics
1 answer:
Salsk061 [2.6K]3 years ago
7 0

Answer:

•Axioms

•Definitions

•Postulate

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Find the recipricol of -b/3
Licemer1 [7]

Answer:

-0.333333333

Step-by-step explanation:

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2 years ago
5 1/6 divided by 2 5/12= 2 4/29 true or false
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5 1/6 divided by 2 5/12 is 2 4/29 so it is true
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Autumn buys eggs and apples at the store.
UNO [17]
The Answer is: 4.73

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1 year ago
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A farmer can spend no more than $4,000 on fertilizer and seeds. The fertilizer costs $2 per pound and seeds cost $20 per pound.
lilavasa [31]

Answer:

The graph in the attached figure

Step-by-step explanation:

Let

f -----> the number of pounds of fertilizer

s ----> the number of pounds of seeds

we know that

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using a graphing tool

see the attached figure

The solution is the triangular shaded area

7 0
3 years ago
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Val needs to find the area enclosed by the figure. The figure is made by attaching semicircles to each side of a 58​-by-58 squar
Savatey [412]

Answer:

We need to find the area of the semicircles + the area of the square.

The area of a square is equal to the square of the lenght of one side.

As = L^2 = 58m^2 = 3,364 m^2

Now, each of the semicircles has a diameter of 58m, and we have that the area of a circle is equal to:

Ac = pi*(d/2)^2 = 3.14*(58m/2)^2 = 3.14(27m)^2 = 2,289.06m^2

And the area of a semicircle is half of that, so the area of each semicircle is:

a =  (2,289.06m^2)/2 = 1,144.53m^2

And we have 4 of those, so the total area of the semicircles is:

4*a = 4* 1,144.53m^2 = 4578.12m^2

Now, we need to add the area of the square 3,364 m^2 + 4578.12m^2 = 7942.12m^2

This is nothing like the provided anwer of Val, so the numbers of val may be wrong.

4 0
3 years ago
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