Answer:
Option 2: (1, 0) and (0, -5)
Step-by-step explanation:
Let's solve this system of equations using the elimination method.
Start by labelling the two equations.
5x -y= 5 -----(1)
5x² -y= 5 -----(2)
(2) -(1):
5x² -y -(5x -y)= 5 -5
Expand:
5x² -y -5x +y= 0
5x² -5x= 0
Factorise:
5x(x -1)= 0
5x= 0 or x -1= 0
x= 0 or x= 1
Now that we have found the x values, we can substitute them into either equations to solve for y.
Substitute into (1):
5(0) -y= 5 or 5(1) -y= 5
0 -y= 5 or -y= 5 -5
y= -5 or -y= 0
y= 0
Thus, the solutions are (0, -5) and (1, 0).
Answer:
Step-by-step explanation:
(3b)³ = 3³·b³ = 27b³
Answer:
Each circle (A, B, and C) contain shapes that all share at least one characteristic. Some shapes are contained in more than one circle because they share more than one characteristic. For example, shape 3 fits the rule for circles A and B, but not circle C. It lies within circles A and B, but not circle C.
Step-by-step explanation:
Answer:
x = 9
Step-by-step explanation:
17x - 1 = 84 + 7x + 5
17x - 7x = 84 + 5 + 1
10x = 90
x = 9
Answer:
55.8
Step-by-step explanation:
44 ^ 2 = 1936
b ^ 2 = 55 .8 ^ 2
51 ^ 2 = 2601