There is no solution for this equation since they have the same slope, x/1. The only difference between these two is that their y intercepts are different meaning that they will be parallel lines that will never intersect among one other. For example, think of it as two separate lines that are have the same slope and never gain more distance/units from one another.

Solve:

To solve, you have to get one of this equations into a Ax+By=C equation form, standard equation. Let’s change y=x+4 into a standard equation.

We have to get x and y together and 4 as C.
So let’s subtract x from both sides;

y=x+4
-x -x
————————
-x+y=4

This is a standard equation.

Now let’s substitute.

take the standard equation and plug in y which is x+4 since there is a equation meaning it’s y=x+4

-x+(x+4)=4

Let’s simplify this mess.

-x+x equals 0. So we are left with 4=4.

Subtract 4 from both sides and we get 0=0

This means there is no solution. Hoped this helped.

8 0

3 years ago

Which side lengths form a right triangle

matrenka [14]

Answer:

need photo or side lengths

3 0

3 years ago

If the sampled population has a mean of 48 and standard deviation of 16, then the mean and the standard deviation for the sampli

Step2247 [10]

Answer:

48 and 4

Step-by-step explanation:

If we assume that $\bar X$ to be the random variable that proceed the normal distribution with mean $\mu$ and a standard deviation $\dfrac{\sigma }{\sqrt{n}}$

Given that:

mean =48

standard deviation = 16

sample size = 16

The population mean is same as the population mean in sampling distribution that is 48.

The standard deviation of the sampling distribution is therefore calculated as:

standard deviation = $\dfrac{\sigma }{\sqrt{n}}$

standard deviation = $\dfrac{16 }{\sqrt{16}}$

standard deviation = $\frac{16}{4}$

standard deviation = 4

Thus; the mean and the standard deviation of the sampling distribution is 48 and 4

3 0

3 years ago

Find the angle between the given vectors to the nearest tenth of a degree.

saul85 [17]

Answer:

Step-by-step explanation:

Given

u = <6, -1>

u = 6i-j

and

v=<7,-4>

v=7i-4j

The formula for angle is:

Let x be the angle

$cos\ x = \frac{u.v}{||u||.||v||}$

where ||u|| is the length and u.v is the dot product or scalar product of both vectors

So,

$||u|| = \sqrt{(6)^2+(-1)^2}\\ = \sqrt{36+1}\\ = \sqrt{37}\\ ||v||=\sqrt{(7)^2+(-4)^2}\\ = \sqrt{49+16}\\ = \sqrt{65}\\$

$u.v = u_1u_2+v_1v_2\\= (6)(7)+(-1)(-4)\\=42+4\\=46$

$cos\ x=\frac{46}{\sqrt{37}\sqrt{65}} \\= \frac{46}{\sqrt{2405} }\\Can\ also\ be\ written\ as:\\= \frac{46}{\sqrt{2405} } * \frac{\sqrt{2405} }{\sqrt{2405}} \\=\frac{46\sqrt{2405} }{2405}$

The calculated angle will be in radians. To find the angle in degrees:

$x = \frac{180}{\pi} cos^{-1} (\frac{46\sqrt{2405} }{2405})\\x = 20.282\\x= 20.3\\$

Hence Option A is correct ..

6 0

4 years ago