3 years ago

The product of (a − b)(a − b) is a2 − b2. A. Sometimes B. Always C. Never

Mathematics

1 answer:

Damm [24]3 years ago

8 0

$(a-b)(a-b)=a^2-2ab+b^2\\\\a^2-2ab+b^2=a^2-b^2\\2b^2=2ab\\b^2=ab\implies a=b \vee b=0$

So, sometimes.

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Lostsunrise [7]

100 Is I was just like oh oh and then you are in the church

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3 years ago

If n = 11 and p = 5 what is the value of the expression 18 - n - 2 + p

yan [13]

Answer:

Step-by-step explanation:

If n = 11 and p = 5, we can just substitute the values in for n and p in the equation 18 - n - 2 + p.

The new equation would be 18 - 11 - 2 + 5.

Using PEMDAS, we get the answer of 10.

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2 years ago

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Step-by-step explanation:

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3 years ago

If 0°<0<90° and sin0=12/13, find cos0 using trigonometric identities.

Aleks04 [339]

here's the solution,

we know :

$\sin( \theta) = \dfrac{perpendicular}{hypotenuse}$

So,

$\dfrac{p}{h} = \dfrac{12}{13}$

so.. let the perpendicular be 12x and hypotenuse be 13x

now,

by applying pythagoras theorem,

$b {}^{2} = h {}^{2} - p {}^{2}$

where,

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h = hypotenuse
p = perpendicular

So,

$b {}^{2} = ({13x})^{2} - ({12x})^{2}$
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so,

$\cos( \theta) = \dfrac{b}{h}$

$\cos( \theta) = \dfrac{5x}{13x}$

$\cos( \theta) = \dfrac{5}{13}$

hope it helps !!

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3 years ago