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Aneli [31]
3 years ago
10

I am confused with everything

Mathematics
1 answer:
notsponge [240]3 years ago
5 0
I think it's x^3+2x^2-4
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467.4 + 0.492 =<br><br>PLS HELP​
ratelena [41]

Answer:

467.892

Step-by-step explanation:

467.4+0.492 =467.892

3 0
3 years ago
Read 2 more answers
What number must be added to 14,056 to result in the sum of 38,773
Vlada [557]
24,717.
What you have to do is subtract 38,773-14,056 and then the answer would be 24,717. So all together 24,717 must be added to result in the sum of 38,773.
14,056+24,717=38,773.
8 0
4 years ago
The prices of tickets for the local rock concert were $16 for Friday night and $28 for Saturday night. The total attendance for
ASHA 777 [7]
Let x: number of tickets that sold on Friday, y: number of tickets that sold on Saturday night

16x+28y=24232
x+y=1090
x=1090-y,
so 16(1090-y)+28y=24232
17440-16y+28y=24232
12y=6792
y=566. As a result, there will be 566 tickets sold on Saturday night. Hope it help!
4 0
3 years ago
Read 2 more answers
Coach Carter buys 4 boxes of crackers from a store to sell at the concession stand. Each box contains 24 packs of crackers. When
lutik1710 [3]

Answer:

I believe that A would be the correct answer im not sure but ill explain from the best of my ability

Step-by-step explanation:

OK SO FOR THE EXPLANATION I BELIEVE THAT IT IS A BECAUSE USUALLY ON THE OTHER QUESTIONS I HAVE HAD IT WOULD USUALLY SPLIT THE FIRST AMOUNT IN HALF AND THAT IS MY EXPLANATION GOOD LUCK

8 0
3 years ago
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You have been tasked with filling 4 ounce and 3 ounce bags from a 41 ounce container of candy.
Alchen [17]

Answer:

A. 3 possible combinations

B. 8 4-ounce's bags and 3 3-ounce's bags

C. 2 4-ounce's bags and 11 3-ounce's bags

D. 8 4-ounce's bags and 3 3-ounce's bags

E. All solutions offer the same revenue.

Step-by-step explanation:

You have been tasked with filling 4 ounce and 3 ounce bags from a 41 ounce container of candy. Let x be the number of 4 ounce bags and y be the number of 3 ounce bags. Then

4x+3y=41.

A. Find all integer solutions:

  • When x=0, then 3y=41 - impossible, because 41 is not divisible by 3.
  • When x=1, then 3y=37 - impossible, because 37 is not divisible by 3.
  • When x=2, then 3y=33, y=11 - possible.
  • When x=3, then 3y=29 - impossible, because 29 is not divisible by 3.
  • When x=4, then 3y=25 - impossible, because 25 is not divisible by 3.
  • When x=5, then 3y=21, y=7 - possible.
  • When x=6, then 3y=17 - impossible, because 17 is not divisible by 3.
  • When x=7, then 3y=13 - impossible, because 13 is not divisible by 3.
  • When x=8, then 3y=9, y=3 - possible.
  • When x=9, then 3y=5 - impossible, because 5 is not divisible by 3.
  • When x=10, then 3y=1 - impossible, because 1 is not divisible by 3.

You get 3 possible combinations.

B. 1. 2 + 11 = 13,

2. 5 + 7 = 12,

3. 8 + 3 = 11.

The minimal number of bags is 11.

C. 1. 2·7+11·5=69 cents

2. 5·7+7·5=70 cents

3. 8·7+3·5=71 cents

The cheapest is 1st solution.

D. 1. 2·6+11·5=67 cents

2. 5·6+7·5=65 cents

3. 8·6+3·5=63 cents

The cheapest is 3rd solution.

E. 1. 2·2+11·1.50=$20.50

2. 5·2+7·1.50=$20.50

3. 8·2+3·1.50=$20.50

All solutions offer the same revenue.

5 0
3 years ago
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