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maks197457 [2]
3 years ago
10

Let f(x) = x + 8 and g(x) = x2 − 6x − 7. Find f(g(2)). (1 point) −7 −3 10 33

Mathematics
1 answer:
qwelly [4]3 years ago
6 0
Since the expressions for f(x) and g(x) are already given, f(g(2)) means to substitute the value of 2 to the expression of g(x), then further substituting the obtained value of g(2) into the expression of f(x). This is shown below:

f(x) = x + 8
g(x) = x^2 - 6x - 7

f(g(x) = x^2 - 6x - 7 + 8 
f(g(2)) = 2^2 - 6(2) + 1
f(g(2)) = 4 - 12 + 1
f(g(2)) = -7

Therefore, the correct answer is -7.
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pickupchik [31]

This sequence be represented as a recursive equation by a1=8 and an=2a1

<u>Step-by-step explanation</u>:

  • 'Recursive' refers to the repetition of a specific process in a sequence.
  • The given sequence is {8,16,32,64}.
  • If the value is 2 times the previous value, then an=2a(n-1)

Let a1=8,

then a2 = 2a(2-1)

⇒ a2 = 2a1

⇒ a2 = 2(8)

⇒ a2 = 16

Similarly,

For a2=16,

⇒ a3 = 2(a2)

⇒ a3 = 2(16)

⇒ a3 = 32

For a3=32,

⇒ a4 = 2(a3)

⇒ a4 = 2(32)

⇒ a4 = 64

∴ The equation is recursive as a1=8 and an=2a1 to follow the sequence.

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2 years ago
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3 years ago
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Four spheres of a radius 6cm just fit inside a cylinder
aksik [14]

Answer:

The space left inside the cyclinder =36π(h - 24)

step-by-step explanation:

Radius of sphere = 6cm

Diameter of cylinder = 12cm

Radius of cylinder = d / 2 = 12 /2 = 6cm

Formula for volume of a sphere = 4/3 πr³

Formula for volume of volume of a cylinder = πr²h

r = radius

h = height

The volume of one sphere = 4/3πr³

Volume of 4 spheres = 4 * 4/3πr³ = 12/3 πr³ = 4πr³

But radius of the sphere = 6cm

Volume of the sphere = 4 * π * 6³

Volume of the sphere = 864π

Let the space left in the cylinder = x

The space left in the cylinder (x) = volume of the cylinder - total volume of the spheres

x = πr²h - 4πr³

Note : both radius = 6cm and we can just substitue it

x = πr² (h - 4r)

x = π*6² (h - 4*6)

x = 36π (h - 24)

The space left inside the cylinder = 36π(h - 24) since we don't know the value of the height of the cylinder.

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