Answer: 105 meters
Step-by-step explanation:
Ostrich's running rate is 63 meters/3 seconds. This can be reduced to 21 meters/second (21 m/s).
(21 m/s)*(5 sec) = 105 meters
Answer:
A subway train arrives every 10 minutes during rush hour. We are interested in the length of time a commuter must wait for a train to arrive. The time follows a uniform distribution. Find u, which is the average length of time a commuter must wait for a train to arrive. Round to one decimal place. = 3
Answer:
1/30 of an hour
Step-by-step explanation:
<h3>
Answer: x = (
y-2)^2 +
5</h3>
In other words, y-2 goes in the first box and 5 goes in the second box.
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Work Shown:
y^2 - 4y - x + 9 = 0
y^2 - 4y + 9 = x
x = y^2 - 4y + 9
x = y^2 - 4y + 4 + 5 .... rewrite 9 as 4+5
x = (y^2-4y+4) + 5
x = (y-2)^2 + 5 .... apply the perfect square factoring rule
So we'll have y-2 go in the first box and 5 goes in the second box
note: One version of the perfect square factoring rule says (a-b)^2 = a^2-2ab+b^2.
