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Mumz [18]
4 years ago
7

Determine whether the series is convergent or divergent by expressing Sn as a telescoping sum. If it is convergent, find its sum

. Show all work.
The sum as n goes from 1 to infinity of ln(n/(n+1))
Mathematics
1 answer:
Inessa05 [86]4 years ago
3 0
<span> i'm going to be slightly extra careful in showing each step. specific, ln [n / (n+a million) ]= ln n - ln(n+a million). So, we've sum(n=a million to infinity) ln [n / (n+a million) ] = lim(ok--> infinity) sum(n=a million to ok) ln [n / (n+a million) ] = lim(ok--> infinity) sum(n=a million to ok) [ln n - ln(n+a million)] = lim(ok--> infinity) (ln a million - ln 2) + (ln 2 - ln 3) + ... + (ln ok - ln(ok+a million)) = lim(ok--> infinity) (ln a million - ln(ok+a million)), for the reason that fairly much all the words cancel one yet another. Now, ln a million = 0 and lim(ok--> infinity) ln(ok+a million) is countless. So, the sum diverges to -infinity. IM NOT COMPLETELY SURE

</span>
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Let f(x) = [infinity] xn n2 n = 1 . Find the intervals of convergence for f. (Enter your answers using interval notation.) Incor
sveta [45]

Answer:

The interval of convergence is -1<x<1

Step-by-step explanation:

To find the interval of convergence of the series, we will use the condition for convergence of a series according to Ratio test.

The solution is as shown in the attachment.

7 0
3 years ago
A circuit contains two capacitors rated at 0.02 microfrads and 0.05 microfrads connected in series the circuits Source voltage i
Neporo4naja [7]

Answer:

  about 0.0143 microfarads

Step-by-step explanation:

The effective capacitance of capacitors in series is the reciprocal of the sum of their reciprocals:

  1/(1/0.02 +1/0.05) = 1/(50+20) = 1/70 ≈ 0.0143 . . . microfarads

8 0
4 years ago
A number is increased by 2 and then multiplied by 3. The result is 24. What is this number
Sav [38]

Answer:

The answer is 6.

Step-by-step explanation:

To find this answer, divide 24 by 3 and you get 8. 8 minus 2 is 6.

3 0
3 years ago
A study is conducted to determine if a newly designed text book is more helpful to learning the material than the old edition. T
CaHeK987 [17]

Answer:

We need to conduct a hypothesis in order to check if the mean is higher than 75, the system of hypothesis are :  

Null hypothesis:\mu \leq 75  

Alternative hypothesis:\mu > 75  

A. One-Tailed

z=\frac{82.2-75}{\frac{10.4}{\sqrt{10}}}=2.189  

p_v =P(z>2.189)=0.0143  

If we compare the p value and the significance level given \alpha=0.01 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis.

Step-by-step explanation:

Data given and notation  

We have the following data: 84 94 80 88 77 68 90 74 96 71

We can calculate the sample mean with the following formula:

\bar X =\frac{\sum_{i=1}^n X_i}{n}

And replacing we got:

\bar X=82.2 represent the sample mean  

\sigma=10.4 represent the population standard deviation  

n=10 sample size  

\mu_o =75 represent the value that we want to test  

\alpha=0.01 represent the significance level for the hypothesis test.  

z would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is higher than 75, the system of hypothesis are :  

Null hypothesis:\mu \leq 75  

Alternative hypothesis:\mu > 75  

A. One-Tailed

Since we know the population deviation, is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:  

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}} (1)  

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic  

We can replace in formula (1) the info given like this:  

z=\frac{82.2-75}{\frac{10.4}{\sqrt{10}}}=2.189  

P-value  

Since is a ONE-TAILED  test the p value would given by:  

p_v =P(z>2.189)=0.0143  

Conclusion  

If we compare the p value and the significance level given \alpha=0.01 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis.

5 0
3 years ago
Select the equivalent expression
svetlana [45]

Answer:

x^-28 / 7^56

Step-by-step explanation:

6 0
3 years ago
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