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3 years ago

The sum of reciprocals of two numbers is 5/6 and the difference is 1/6. Find the numbers.

2 answers:

8 0

Hello,
Let's assume a and b the 2 numbers with a<b

1/a+1/b=5/6 (1)

1/a-1/b=1/6 (2)
(1)+(2)==>1/a+1/a=5/6+1/6==>2/a=1==>a=2

(1)==>1/b=5/6-1/2==>1/b=5/6-3/6==>1/b=1/3==>b=3

dsp733 years ago

7 0

X=2
, y=3

this is the answer

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Noah built a fenced dog run that is 8 yards long and 6 yards wide. He placed posts at every corner and every yard along the leng

bagirrra123 [75]

To solve this problem first find the perimeter of the rectangle by using the formula P= 2(L+W).
Plug in your number and you get the number 28.
Now, because Noah is putting in a post at every yard and our answer is already in yards we are done.

Noah will need 28 post to build the dog run.

P=2(8+6)
P=2(14)
P=28

Hope this helps :-)

7 0

3 years ago

Every day a kindergarten class chooses randomly one of the 50 state flags to hang on the wall, without regard to previous choice

Svet_ta [14]

Answer:

a.) P(x = X) = $\frac{1}{50}$

b.) $\frac{1}{50} \times\frac{1}{50} \times\frac{1}{50} = \frac{1}{125000}$

c.) 0.00118

Step-by-step explanation:

The sample space Ω = flags of all 50 states

a.) Any one of the flags is randomly chosen. Therefore we can write the

probability measure as P(x = X) = $\frac{1}{50}$ , for all the elements of the sample

space, that is for all x ∈ Ω.

b.) the probability that the class hangs Wisconsin's flag on Monday,

Michigan's flag on Tuesday, and California's flag on Wednesday

= $\frac{1}{50} \times\frac{1}{50} \times\frac{1}{50} = \frac{1}{125000}$

c.) the probability that Wisconsin's flag will be hung at least two of the three days

= Probability that Wisconsin's flag will be hung on two days + Probability that Wisconsin's flag will be hung on three days

= P(x = 2) + P(x = 3)

= $(\binom{3}{2}\times \frac{1}{50} \times \frac{1}{50}\times \frac{49}{50}) + (\binom{3}{3}\times \frac{1}{50} \times \frac{1}{50}\times \frac{1}{50})\\$

= $\frac{147}{125000} + \frac{1}{125000}$

= $\frac{148}{125000}$

= 0.00118

7 0

3 years ago

An ant went 2 meters away from its nest searching for food. The next time, the ant went 3 meters away. Each successive time the

seropon [69]

Answer:

The first time, the ant went 2m away, then we have a₁ = 2m

The second time, the ant went 3m away, then we have a₂ = 3m

The next time, the ant went a distance equal to the sum of the two previous ones, so we can write it in a general case as:

aₙ = aₙ₋₁ + aₙ₋₂

Only if n > 2.

then the third time, we have n = 3.

a₃ = a₂ + a₁ = 2m + 3m = 5m

a₄ = a₃ + a₂ = 3m + 5m = 8m

a₅ = a₄ + a₃ = 5m + 8m = 13m

This means that in the fifth trip, the ant went 13 meters away from its nest.

And if we consider the fact that the ant must go and return, then it will move a total distance of 13 meters two times, or 2*13m = 26 meters.

8 0

3 years ago

WILL GIVE BRAINIEST<br> HELP PLEASE AND THANK YOU c:

galben [10]

I do believe it might be the first option.

5 0

3 years ago

Mary's sink was clogged, so she called a plumber. The plumber charges a service fee of $50 as well as $25 for each hour he worke

Katen [24]

Answer: The plumber worked 3.42 hours

Step-by-step explanation:

25h+50=135.50 (minus 50 to both sides)

25h=85.50 (divide 25 to both sides)

h=3.42

Check:

25(3.42)+50=135.50

85.50+50=135.50

135.50=135.50

6 0

3 years ago