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Scorpion4ik [409]
2 years ago
9

BRAINLIEST ASAP!!!

Mathematics
1 answer:
Anarel [89]2 years ago
5 0
Part A: the radicand is the same as the discriminant, therefore is b2 - 4ac
In 9x^2 - 16x + 60 = 0, a = 9, b = -16, c = 60
so b2 - 4ac =
{b}^{2}  - 4ac =  {( - 16)}^{2}  - 4(9)(60) \\  = 256 - 2160 = 1904 \\  \sqrt{1904}  =  + 43.63 \: and \:  - 43.63

Part B: Solve 4x^2 + 8x - 5 = 0
What would make 8? (5×2)-2 = 8, so:
(2x+5)(2x-1) = 0
2x+5 = 0
2x = -5
x = -5/2
2x-1 = 0
2x = 1
x = +1/2
So the solutions are: -5/2, +1/2
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natali 33 [55]

Answer:

-1.8 =x

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12(x+3)=-8x

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12x +36 = -8x

Subtract 12x from each side

12x-12x +36 = -8x-12x

36 = -20x

Divide each side by -20

36/-20 = -20x/-20

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Changing to decimal form

-1.8 =x

4 0
3 years ago
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Which list shows the numbers in order from least value to greatest value
Alina [70]
The answer is H

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Oh and by the way if you don’t know how to turn a fraction into a decimal you simply divide the top number by the bottom number for example 1/2 you take 1 and divide it by 2 which gives you .5 or 12/13 = .923076 hope this makes sense and that this helped
8 0
3 years ago
In one year, the Perseid meteor shower had a meteor appear every 1 1/5 minutes on average. That same year, the Leonid meteor sho
RoseWind [281]

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1 + \frac{1}{5} = 1 + 0.2 = 1.2

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1 meteor - 1.2 minutes.

x meteors - 525600 minutes.

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x = \frac{525600}{1.2}

x = 438000

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4 + \frac{2}{3} = 4.67

One each 4.67 minutes. How many during an year.

1 meteor - 4.67 minutes.

x meteors - 525600 minutes.

4.67x = 525600

x = \frac{525600}{4.67}

x = 112548

112,548 meteors fell during the Leonid Shower.

How many more meteors fell during the Perseid meteor shower?

438,000 - 112,548 = 325,452

325,452 more meteors fell during the Perseid meteor shower

5 0
2 years ago
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sertanlavr [38]
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