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3 years ago

△FOD~△HOG. Identify the coordinates of D and the scale factor. HELP PLEASE!!

Mathematics

1 answer:

cupoosta [38]3 years ago

8 0

Answer:

Option D. $(0,-20/3)$ , $\frac{2}{3}$

Step-by-step explanation:

we know that

If two figures are similar, then the ratio of its corresponding sides is equal

$\frac{OH}{OF}=\frac{OG}{OD}$

substitute values and solve for OD

$\frac{6}{4}=\frac{10}{OD}$

$OD=10*4/6=20/3$

therefore

the coordinate of point D is $(0,-20/3)$

the scale factor is equal to $\frac{OF}{OH}=\frac{4}{6}=\frac{2}{3}$

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Draw a rectangle that has a perimeter of 20 units and an area of 25 square units

marissa [1.9K]

<h2>Explanation:</h2><h2></h2>

For any rectangle the dimensions are given by:

$w:width \\ \\ l:Length$

So the perimeter (P) is given by the following equation:

$P=2(w+l)$

And the area is:

$A=w\times l$

We know that:

$P=20units \\ \\ A=25units^2$

By substituting:

$20=2(w+l) \\ \\ \therefore w+l=10 \ \ldots eq1 \\ \\ \\ 25=w\times l \ldots eq2$

Solving for $w$ from eq1:

$w=10-l$

Substituting into eq2:

$25=(10-l)\times l$

Then:

$\text{Solving for l:} \\ \\ \\ 10l-l^2=25 \\ \\ 10l-l^2-25=25-25 \\ \\ -l^2+10l-25=0 \\ \\ x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a} \\ \\ \\ a=-1,\:b=10,\:c=-25 \\ \\ \\ l_{1,\:2}=\frac{-10\pm \sqrt{10^2-4\left(-1\right)\left(-25\right)}}{2\left(-1\right)} \\ \\ l_{1,\:2}=\frac{-10\pm \sqrt{0}}{2\left(-1\right)} \\ \\ l=5$

Solving for w:

$w=10-5=5$

So this rectangle is a square and is shown below.

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3 years ago

Which equation is equal to 4a+2b=10

stealth61 [152]

A=5/2-1/2b is equal to 4a+2b=10

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4 years ago

PLEASE HELP ME WITH THIS!! ILL GIVE BRAINLIEST.

Lubov Fominskaja [6]

Answer:

1. Correct

2. Correct

3. Correct

4. Correct

5. Incorrect

6. Correct

7. Incorrect

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Step-by-step explanation:

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3 years ago

Please help

dem82 [27]

Answer:

Step-by-step explanation:

1) we have to solve the associated equation

-16x^2 + 24x + 16 = 0

-2x^2 + 3x + 2 = 0

2x^2 -3x -2 = 0

Δ = 9 + 16 = 25

x1 = (3 + 5)/4= 2

x2 = (3 - 5)/4 =-1/2

the x intercepts are -1/2 and 2

2) a maximum because the parabola opens downwards (the first term is negative)

V(x) = -b/2a = -24/-32 = 3/4

V(y) = -16(9/16) + 24(3/4) + 16 = -9+18 + 16 = 25

V(3/4,25)

3) for draw a parabola is are necessary the coordinates of the vertex and of two points: one that lies to left of the vertex, and one that lies on the right to the vertex.

So we already have the necessary informations to draw it.

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3 years ago

Simplify by finding the product of the polynomials below. Then Identify the degree of your answer. When typing your answer use t

nexus9112 [7]

Solution:

Given:

$(2x^2+2x+1)(4x-1)$

To get the product of the polynomial; we use the distributive property of multiplication.

$a(b+c)=ab+ac$

$\begin{gathered} (4x-1)(2x^2+2x+1) \\ 4x(2x^2+2x+1)-1(2x^2+2x+1) \\ =8x^3+8x^2+4x-2x^2-2x-1 \\ \text{Collecting similar terms together and simplifying further;} \\ =8x^3+8x^2-2x^2+4x-2x-1 \\ =8x^3+6x^2+2x-1 \end{gathered}$

Therefore, the product of the polynomials is;

$8x^3+6x^2+2x-1$

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1 year ago