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stealth61 [152]
1 year ago
5

Simplify by finding the product of the polynomials below. Then Identify the degree of your answer. When typing your answer use t

he carrot key ^ (press shift and 6) to indicate an exponent. Type your terms in descending order and do not put any spaces between your characters. (2x^2+2x+1)(4x-1) This simplifies to: AnswerThe degree of our simplified answer is: Answer

Mathematics
1 answer:
nexus9112 [7]1 year ago
3 0

Solution:

Given:

(2x^2+2x+1)(4x-1)

To get the product of the polynomial; we use the distributive property of multiplication.

a(b+c)=ab+ac

\begin{gathered} (4x-1)(2x^2+2x+1) \\ 4x(2x^2+2x+1)-1(2x^2+2x+1) \\ =8x^3+8x^2+4x-2x^2-2x-1 \\ \text{Collecting similar terms together and simplifying further;} \\ =8x^3+8x^2-2x^2+4x-2x-1 \\ =8x^3+6x^2+2x-1 \end{gathered}

Therefore, the product of the polynomials is;

8x^3+6x^2+2x-1

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4. 6t -5+5t = 105 (t = 4; t = 7;t = 10)
prohojiy [21]

Answer:

t = 10.

Step-by-step explanation:

We can combine like terms, getting 11t - 5 = 105.

Add both sides by 5, getting 11t = 105 + 5 = 110.

We can then divide both sides by 11, getting t = 10.

4 0
3 years ago
<img src="https://tex.z-dn.net/?f=f%28x%29%3D%7C3x-5%7C%2B7x%5C%5Cg%28x%29%3D-2x%2B9%5C%5Cwhat%20is%20%5C%5C%20%28f%2Bg%29%28x%2
Sergio [31]

Given:

The functions are:

f(x)=|3x-5|+7x

g(x)=-2x+9

To find:

The function (f+g)(x).

Solution:

We have,

f(x)=|3x-5|+7x

g(x)=-2x+9

We know that,

(f+g)(x)=f(x)+g(x)

On substituting the values of given functions, we get

(f+g)(x)=|3x-5|+7x+(-2x+9)

(f+g)(x)=|3x-5|+7x-2x+9

(f+g)(x)=|3x-5|+5x+9

Therefore, the required function is (f+g)(x)=|3x-5|+5x+9.

7 0
3 years ago
A line has a slope of -3 and y-intercept of 2.
Pie

AnswA line can be written in the form y = mx + b where m is the slope and b is the y intercept.

Since the slope is given as 4, the equation will be y = 4x + b

Plugging in the point (2,1) to the equation we get 1 = 4(2) + b or 1 = b + 8

Solving for b gives b = -7 so the equation will be y = 4x - 7er:

Step-by-step explanation:

5 0
3 years ago
What is the solution set for this linear-quadratic system of equations?
Lostsunrise [7]
Y - x - 3 = 0
y = x + 3

y = x^2 - x - 12
x + 3 = x^2 - x - 12
x^2 - x - 12 - x - 3 = 0
x^2 - 2x - 15 = 0
(x - 5)(x + 3) = 0

x - 5 = 0     y = x + 3
x = 5          y = 5 + 3
                  y = 8

x + 3 = 0     y = x + 3
x = -3          y = -3 + 3
                   y = 0

so ur solutions are : (5,8) and (-3,0)
3 0
4 years ago
Read 2 more answers
What is the correct answer to this please
murzikaleks [220]
I am sorry if i am wrong but i keep getting 6,4
3 0
3 years ago
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