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Dafna11 [192]
3 years ago
10

Please help

Mathematics
1 answer:
dem82 [27]3 years ago
4 0

Answer:

Step-by-step explanation:

1) we have to solve the associated equation

-16x^2 + 24x + 16 = 0

-2x^2 + 3x + 2 = 0

2x^2 -3x -2 = 0

Δ = 9 + 16 = 25

x1 = (3 + 5)/4= 2

x2 = (3 - 5)/4 =-1/2

the x intercepts are -1/2 and 2

2) a maximum because the parabola opens downwards (the first term is negative)

V(x) = -b/2a = -24/-32 = 3/4

V(y) = -16(9/16) + 24(3/4) + 16 = -9+18 + 16 = 25

V(3/4,25)

3) for draw a parabola is are necessary the coordinates of the vertex and of two points: one that lies to left of the vertex, and one that lies on the right to the vertex.

So we already have the necessary informations to draw it.

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LHL in not equal to RHL , Therefore the limit does not exists , Option D is the answer.(none)

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The limit of a function at a certain point is the value that the function approaches as the argument of the function approaches the same point.

It is given that

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