A number that is not an integer
1 answer:
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Answer:
8, 10
Step-by-step explanation:
Multiplying the equation by the product of the denominators, we have ...
40(x+2) +40x = 9x(x+2)
80x +80 = 9x^2 +18x . . . . eliminate parentheses
9x^2 -62x -80 = 0 . . . . . . put in standard form
9x^2 -72x +10x -80 = 0 . . . prepare to factor by grouping
9x(x -8) +10(x -8) = 0 . . . . . factor pairs of terms
(9x +10)(x -8) = 0
Solutions are ...
x = -10/9 and x = 8
The integers are 8 and 10.
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<em>Comment on the attachment</em>
I find a graphing calculator to be a nice tool for solving these. It finds zeros easily, so writing the equation so it equals zero is a useful first step.
