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nignag [31]
3 years ago
5

The weights of NCAA lacrosse players are approximately normally distributed with a mean of 182 lbs and a standard deviation of 1

3.1 lbs.
. a) Find the probability that a player will have a weight between 163 lbs and 191 lbs. (6 points)

. b) How much would a lacrosse player weigh if he was lighter than 75% of the other players? (5 points)

Show your work in proper format on separate paper making sure you've answered all parts of the question.

Then, snap a pic of your work and upload it as your answer.

Be sure your upload is the correct file.
Mathematics
1 answer:
Marizza181 [45]3 years ago
4 0

Answer:

What can I do for you

Step-by-step explanation:

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1760/8 = 220
So the unit rate is 220
5 0
3 years ago
If f(x)=-5^x-4 and g(x)=-3x-2 find (f-g)(x)
sukhopar [10]

Answer:

(f-g)(x) = 5^x +3x -2

Step-by-step explanation:

The value (f-g)(x) means subtract the function g from f. This can be done by combining only like terms between each.

(f-g)(x) = 5^x - 4 -(-3x-2)\\(f-g)(x) = 5^x - 4 +3x + 2\\(f-g)(x) = 5^x +3x -2

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3 years ago
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How many positive integers between 1000 and 9999 inclusive
bekas [8.4K]

Answer:

Step-by-step explanation:

a.

first number is  1000-1+9=1008

9)1000(1

    9

-------

     10

       9

    -----

       10

         9

       ----

         1

       ----

last number is 9999

9| 9999

  ---------

    1111 |0

    --------

9999=1008+(n-1)9

9999-1008=(n-1)9

n-1=8991/9=999

n=999+1=1000

b.

first digit=1000

last digit=9999-1=9998

2 |9999

  ---------

  |4999|1

9998=1000+(n-1)2

(n-1)2=9998-1000=8998

n-1=4499

n=4499=1=5000

c.not sure

d.

total  numbers=9000

9999=1000+(n-1)1

9999-1000=n-1

n=8999+1=9000

numbers divisible by 3=3000

first number=1002

last number=9999

9999=1002+(n-1)3

(n-1)3=9999-1002=8997

n-1=2999

n=2999+1=3000

numbers not divisible by 3=9000-3000=6000

e.

numbers divisible by 5=1800

first number=1000

last number=9995

9995=1000+(n-1)5

(n-1)5=9995-1000=8995

n-1=1799

n=1799+1=1800

numbers divisible by 7=1286

7 | 1000

  ---------

  |  142-6

1000-6+7=1001

7 | 9999

  |---------

    1428-3

9999-3=9996

first digit=1001

last digit=9996

9996=1001+(n-1)7

(n-1)7=9996-1001=8995

n-1=1285

n=1285+1=1286

numbers divisible by 35=257

first digit=1015

35 ) 1000 ( 28

        70

       ----

        300

        280

        ------

           20

           ---

1000-20+35=1015

35)9999(285

     70

    ----

     299

     280

     -----

        199

        175

        ----

          24

         ----

last digit=9999-24=9975

9975=1015+(n-1)35

(n-1)35=9975-1015=8960

n-1=8960/35=256

n=257

reqd. numbers=1800+1286-257=3019

7 0
3 years ago
Find the volume. I will award best answer!! Please help me
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Answer:

1512

Step-by-step explanation:

18 times 21 times 8 = 3024

since it's a triangular prism, u half it

3024 div 2 = 1512

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Answer:T


Step by Step explanation
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