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VLD [36.1K]
3 years ago
9

Determine the standard form of the equation of the line that passes through (-6,6) and (3,-2)

Mathematics
1 answer:
Simora [160]3 years ago
4 0

Answer:

y=(8/9)x + 4 and 2/3

Step-by-step explanation:

the slope of this line:

change in y/change in x

change in y=6-(-2)=8

change in x=-6-3=-9

change in y/change in x= 8/9

8/9 is the slope, so you plug it in for m in the standard form equation. You then use one point's x and y values to substitute for x and y in the equation, and solve for b, which is the y intercept

y=mx+b

y=(8/9)x+b

-2=(8/9)*3+b

-2=8/3+b

-4 and 2/3=b

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Solve the following differential equations or initial value problems. In part (a), leave your answer in implicit form. For parts
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Answer:

(a) (y^5)/5 + y^4 = (t^3)/3 + 7t + C

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Step-by-step explanation:

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2ln(t + 1) - lnt + lnC = -1/y

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-1 = ln(4C)

4C = e^(-1)

C = (1/4)e^(-1) ≈ 0.09

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