the problem isnt that hard. you need to do the distributive property or FOIL with (m+3) four different times. The answer would be
M^4 + 12M^3 +54M^2 +108M +81
Answer: ![(0.5,8.5)](https://tex.z-dn.net/?f=%280.5%2C8.5%29)
Step-by-step explanation:
We need to use the following formula to find the Midpoint "M":
![M=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})](https://tex.z-dn.net/?f=M%3D%28%5Cfrac%7Bx_1%2Bx_2%7D%7B2%7D%2C%5Cfrac%7By_1%2By_2%7D%7B2%7D%29)
Given the points (-5,13) and (6,4) can identify that:
![x_1=-5\\x_2=6\\\\y_1=13\\y_2=4](https://tex.z-dn.net/?f=x_1%3D-5%5C%5Cx_2%3D6%5C%5C%5C%5Cy_1%3D13%5C%5Cy_2%3D4)
The final step is to substitute values into the formula.
Therefore, the midpoint of the segment between the points (-5,13) and (6,4) is:
![M=(\frac{-5+6}{2},\frac{13+4}{2})\\\\M=(\frac{1}{2},\frac{17}{2})\\\\M=(0.5,8.5)](https://tex.z-dn.net/?f=M%3D%28%5Cfrac%7B-5%2B6%7D%7B2%7D%2C%5Cfrac%7B13%2B4%7D%7B2%7D%29%5C%5C%5C%5CM%3D%28%5Cfrac%7B1%7D%7B2%7D%2C%5Cfrac%7B17%7D%7B2%7D%29%5C%5C%5C%5CM%3D%280.5%2C8.5%29)
Answer : 4 times
Here it's given that ,
- The height and base of the butterfly sitting on the stem (red butterfly) is two times greater than the height and base of the butterfly sitting on the flower .
And we need to find out how many times the area of red winged butterfly is greater than that of sitting on the flower (blue butterfly) .
Let us take ,
- base of blue butterfly be b
- height of blue butterfly be h
- Area be A .
Then ,
- base of red butterfly will be 2b .
- height of red butterfly will be 2h .
- Area be A' .
We know that ,
→ area of the triangle = 1/2 × base × height
So that ,
→ A/A' = (1/2 * b * h) ÷ (1/2 *2b *2h)
→ A/A' = bh/4bh
→ A/A' = 1/4
→ A' = 4A
<u>Henceforth</u><u> the</u><u> area</u><u> of</u><u> </u><u>blue</u><u> butterfly</u><u> is</u><u> </u><u>4</u><u> </u><u>times </u><u>greater</u><u> than</u><u> </u><u>that</u><u> of</u><u> </u><u>red </u><u>winged</u><u> butterfly</u><u> </u><u>.</u>
I hope this helps.