Count the possible combinations of r letters chosen from the given list P.Q,R,S,T,U; r = 2
1 answer:
Answer:
<h2>There are 30 possible combinations of picking two letters.</h2>Step-by-step explanation:
The combinations are defined as
Where is the total number of elements and
is the number of letter we are gonna picke, which is two. Using this information, we have
Therefore, there are 30 possible combinations of picking two letters.
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Answer:
The probability that exactly 1 student is using Internet Explorer and at least 3 students are using Chrome is 0.1350.
Step-by-step explanation:
Denote the events as follows:
<em>C</em> = a student uses Google chrome
<em>E</em> = a student uses Internet explorer
<em>F</em> = a student uses Firefox
<em>M</em> = a student uses Mozilla
<em>S</em> = a student uses Safari
Given:
P (C) = 0.50
P (E) = 0.09
P (F) = 0.10
P (M) = 0.05
P (S) = 0.26
A sample of <em>n</em> = 5 students is selected.
The probability that exactly 1 student is using Internet Explorer and at least 3 students are using Chrome is:
P (E = 1 ∩ C ≥ 3) = P (E = 1 ∩ C = 3) + P (E = 1 ∩ C = 4) - P (E = 1 ∩ C = 5)
The probability distribution of a student using any of the browser is Binomial.
Compute the probability that exactly 1 student is using Internet Explorer and at least 3 students are using Chrome as follows:
P (E = 1 ∩ C ≥ 3) = P (E = 1 ∩ C = 3) + P (E = 1 ∩ C = 4) - P (E = 1 ∩ C = 5)
= P (E = 1) [P (C = 3) + P (C = 4) - P (C = 5)]
Thus, the probability that exactly 1 student is using Internet Explorer and at least 3 students are using Chrome is 0.1350.