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qaws [65]
3 years ago
8

HELP!!!! I NEED HELP WITH THIS.

Mathematics
1 answer:
Artist 52 [7]3 years ago
7 0

Answer:

\large\boxed{A=x^2+23x+49}

Step-by-step explanation:

Subtract the area of a square (x + 1) × (x + 1)

from the area of a rectangle (x + 10) × (2x + 5)

The area of a square:

A_s=(x+1)(x+1)            <em>use FOIL: (a + b)(c + d) = ac + ad + bc + bd</em>

A_s=(x)(x)+(x)(1)+(1)(x)+(1)(1)=x^2+x+x+1=x^2+2x+1

The area of a rectangle:

A_r=(x+10)(2x+5)              <em>use FOIL</em>

A_r=(x)(2x)+(x)(5)+(10)(2x)+(10)(5)=2x^2+5x+20x+50=2x^2+25x+50

The area of a figure:

A=A_r-A_s

Substitute:

A=(2x^2+25x+50)-(x^2+2x+1)=2x^2+25x+50-x^2-2x-1

<em>combine like terms</em>

A=(2x^2-x^2)+(25x-2x)+(50-1)=x^2+23x+49

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